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Anon25 [30]
3 years ago
10

Ram has power of 550 watt. What does it mean?

Physics
1 answer:
WARRIOR [948]3 years ago
4 0
It means you can do 550 Newton Meters of work every second. Power is the rate of doing work, I hope this helps
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Juans mother drives 7.25 miles southwest to her favorite shopping mall. What is the average velocity of her automobile if she ar
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21.75 Miles Per Hour

I got this by multiplying 7.25(3) because I know 20 minutes is 1/3 of 1 he
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Speed is different from velocity because
shtirl [24]

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A. velocity has a direction .. .

with magnitude too but speed has only magnitude

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When the mirror is rotated, the normal will turn as well, but will the incident Ray and reflected ray turn?
Inessa [10]

When a mirror is rotated . . .

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6 0
3 years ago
You and your friends find a rope that hangs down 19m from a high tree branch right at the edge of a river. You find that you can
tangare [24]

Answer:

Explanation:

Given

length of rope L=19\ m

velocity while running v=2\ m/s

when the person jumps off the bank and hang on the rope then we can treat the person as pendulum with Time period T which is given by

T=2\pi \sqrt{\frac{L}{g}}

T=2\pi \sqrt{\frac{19}{9.8}}

T=2\pi \times 1.392

T=8.74\ m/s

Greatest Possible distance will be covered when person reaches the other extreme end  of assumed pendulum (velocity=zero)

therefore he must hang on for 0.5 T time

time=0.5\times 8.74=4.37\ s

5 0
3 years ago
A multimeter in an RL circuit records an rms current of 0.600 A and a 50.0-Hz rms generator voltage of 110 V. A wattmeter shows
jeka57 [31]

Answer:

(a) The impedance in the circuit is Z=183.33\Omega.

(b)The resistance is R=38.89\Omega.

(c) The inuctance is 0.57 H.

Explanation:

(a)

The expression for the impedance is as follows:

Z=\frac{V_rms}{I_rms}

Here, V_rms is the rms voltage and I_rms is the rms current.

PutV_rms=110 V and I_rms=0.600 A.

Z=\frac{110}{0.600}

Z=183.33\Omega

Therefore, the impedance in the circuit is Z=183.33\Omega.

(b)

The expression for the average power is as follows;

P_{a}=I_{rms}^{2}R

Here, P_{a} is the average power and R is the resistance.

Calculate the resistance by rearranging the above expression.

R=\frac{P_{a}}{I_{rms}^{2}}

Put P_{a}=14W and

R=\frac{14}{{0.600}^{2}}

R=38.89\Omega

Therefore, the resistance is R=38.89\Omega.

(c)

The expression for the impedance is as follows;

Z^{2}=R^{2}+X_{L}^{2}

Here,X_{L} is the inductive reactance.

Put Z=183.33\Omega and R=38.89\Omega.

(183.33)^{2}=(38.89)^{2}+X_{L}^{2}

X_{L}=179.16\Omega

The expression for the inductive reactance in terms of  frequency is as follows;

X_{L}=2\pi fL

Here, L is the inductance.

Calculate the inductance by rearranging the above expression.

L=\frac{X_{L}}{2\pi f}

Put X_{L}=179.16\Omega and f=50Hz.

L=\frac{179.16}{2\pi (50)}

L=0.57 H

Therefore, the inuctance is 0.57 H.

4 0
3 years ago
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