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2 years ago

Ram has power of 550 watt. What does it mean?

Physics

1 answer:

WARRIOR [948]2 years ago

4 0

It means you can do 550 Newton Meters of work every second. Power is the rate of doing work, I hope this helps

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Um corpo de massa igual a 2kg move-se com velocidade constante num plano horizontal sem atrito, conforme a figura. Em seguida, e

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3 years ago

RHOOLIOTTO<br> How much mass would be needed to produce 2.7 x 1016 J?

Radda [10]

E = mc^2
m = e/c^2
m = 2.7*10^16/(300000^2)
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3 years ago

__________ are combating competitive pressures by providing better value with private-label merchandise; adding new value-added

Neko [114]

Answer:

convinience store

Explanation:

convenience store are more like retail store providing everyday goods.

since this kind of store is usually small, maybe not as big as a department store, there is a growing number of such stores creating competitive pressures as such many are providing better value with private-label merchandise (more like re-branding or personalizing the products in the store)

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3 years ago

calculate earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the s

IceJOKER [234]

Answer:

Hello your question is incomplete below is the complete question

Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000

answer : V = 1.624* 10^-5 m/s

Explanation:

First we have to calculate the value of a

a = 93 * 10^6 mile/m * 1609.344 m

= 149.668 * 10^8 m

next we will express the distance between the earth and the sun

$r = \frac{a(1-E^2)}{1+Ecos\beta }$ --------- (1)

a = 149.668 * 10^8

E (eccentricity ) = ( 1/60 )^2

$\beta$ = 90°

input the given values into equation 1 above

r = 149.626 * 10^9 m

next calculate the Earths velocity of approach towards the sun using this equation

$v^2 = \frac{4\pi^2 }{r_{c} }$ ------ (2)

Note :

Rc = 149.626 * 10^9 m

equation 2 becomes

( $V^2 = (\frac{4\pi^{2} }{149.626*10^9})$

therefore : V = 1.624* 10^-5 m/s

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3 years ago

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3 years ago