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3 years ago

What is the product of 510 and 47?

Mathematics

1 answer:

nordsb [41]3 years ago

8 0

510 times 47 equals 23970
hope it helps!

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Which choices are equivalent to the expression below? Check all that apply. 6√3

Westkost [7]

Answer:

case A. $\sqrt{18}*\sqrt{6}$

case B. $\sqrt{108}$

case E. $\sqrt{3}*\sqrt{36}$

Step-by-step explanation:

we have

$6\sqrt{3}$

we know that

$6\sqrt{3}=\sqrt{36*3}=\sqrt{108}$

<u>Verify each case</u>

case A) $\sqrt{18}*\sqrt{6}$

$\sqrt{18}*\sqrt{6}=\sqrt{18*6}=\sqrt{108}$

therefore

$\sqrt{18}*\sqrt{6}$ is equivalent to $6\sqrt{3}$

case B) $\sqrt{108}$

$\sqrt{108}$ is equivalent to $6\sqrt{3}$

case C) $\sqrt{3}*\sqrt{6}$

$\sqrt{3}*\sqrt{6}=\sqrt{18}$

therefore

$\sqrt{18}$ is not equivalent to $6\sqrt{3}$

case D) $\sqrt{54}$

$\sqrt{54}$ is not equivalent to $6\sqrt{3}$

case E) $\sqrt{3}*\sqrt{36}$

$\sqrt{3}*\sqrt{36}=\sqrt{108}$

therefore

$\sqrt{3}*\sqrt{36}$ is equivalent to $6\sqrt{3}$

case F) $108$

$108$ is not equivalent to $6\sqrt{3}$

6 0

2 years ago

Kelso sold digital cameras on her website. She bought the cameras for $65 each and included 60% markup to get the selling price.

Butoxors [25]

Find 60% of 65 then add it to 65

0.6 x 65 = 39

now add it to 65:

39 + 65 = 104

They are selling them for 104$

6 0

3 years ago

Find the 4th term in the following sequence (n = 4)

lisabon 2012 [21]

this formula, doesn't rely on a product, relies on a "sum", or is namely an arithmetic sequence, aₙ₋₁ -3 is another way of saying, the value of the previous term minus 3, so it relies on the ordinal value of a term, so is an recursive formula, well, let's get it when n = 4.

$\begin{array}{ccll} order&term&value\\ \cline{1-3} 1&a_1&8\\ 2&a_2&a_{2-1}-3\\ &&a_1-3\\ &&8-3\\ &&5\\ 3&a_3&a_{3-1}-3\\ &&a_2-3\\ &&2\\ 4&a_4&a_{4-1}-3\\ &&a_3-3\\ &&2-3\\ &&-1 \end{array}$

5 0

2 years ago

A population of bacteria is introduced into a culture. the number of bacteria P can be modeled by P=500(1+4t/(50+t^2 )) where t

Dennis_Churaev [7]

P(t)=500(1+4t/(50+t^2 ))

P'(t) = 500 [(50+t^2).4 - 4t.2t]/(50+t^2)^2

by the quotient rule

500 (-4t^2 + 200)/(t^2 + 50)^2

Hence

P'(2) = 500 . (-16 + 200)/54^2 ~= 31.6

6 0

3 years ago

The two intervals (114.9, 115.7) and (114.6, 116.0) are confidence intervals (computed using the same sample data) for μ = true

kenny6666 [7]

Answer:

115.3 hertz

Step-by-step explanation:

For either interval, the value of the sample mean is given by the average of the lower and upper bound of the confidence interval. Since both intervals were constructed by using the same sample, both values should be equal.

For the first interval:

$M=\frac{114.9 + 115.7}{2} \\M=115.3\ hertz$

For the second interval:

$M=\frac{114.6 + 116.0}{2} \\M=115.3\ hertz$

4 0

3 years ago