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Alenkinab [10]
3 years ago
12

Which solution is a buffer? • 0.100 m hno2 and 0.100 m hcl • 0.100 m hno3 and 0.100 m nano3 • 0.100 m hno2 and 0.100 m nacl • 0.

100 m hno2 and 0.100 m nano2?
Chemistry
1 answer:
DENIUS [597]3 years ago
4 0
A buffer has roughly equal concentrations of a weak acid and its conjugate base. The only acids in the question are HNO3 and HNO2. HNO3 is a strong acid, so it can’t be used for a buffer. The first option has HNO2 and hydrochloric acid, which won’t supply the conjugate base of HNO2, which is NO2^-1. NaCl isn’t an acid or a base, so we can eliminate that as well. That leaves us with HNO2 and NaNO2. Group 1 metals are spectators in acid-base equilibria, so we can ignore Na once it disassociates. That will give us .1M HNO2 and .1M NO2^-1, which is what we want.
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through thermal energy

Explanation:

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A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t
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Answer:

A. endothermic.

A. Yes, absorbed.

Explanation:

Let's consider the following thermochemical equation.

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)  ΔH = 182 kJ

The enthalpy of the reaction is positive (ΔH > 0), which means that the reaction is endothermic.

182 kJ are absorbed when 2 moles of HgO react (molar mass 216.59 g/mol). The heat absorbed when 72.8 g of HgO react is:

72.8g.\frac{1mol}{216.59g} .\frac{182kJ}{2mol} =30.6kJ/mol

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3 years ago
PLEASE HELP!!!!!!!!!
andreev551 [17]

The average atomic mass of the imaginary element : 47.255 amu

<h3>Further explanation  </h3>

The elements in nature have several types of isotopes  

Isotopes are elements that have the same Atomic Number (Proton)  

Atomic mass is the average atomic mass of all its isotopes  

Mass atom X = mass isotope 1 . % + mass isotope 2.% ..

isotope E-47 47.011 amu, 87.34%

isotope E-48 48.008 amu, 6.895

isotope E-49 50.009 amu, 5.77%

The average atomic mass :

\tt avg~mass=0.8734\times 47.011+0.06895\times 48.008+0.0577\times 50.009\\\\avg~mass=41.059+3.310+2.886\\\\avg~mass=47.255~amu

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2 years ago
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irina [24]
The liquid nitrogen freezes the balloon and shatters it on contact
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3 years ago
If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
Natali5045456 [20]
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
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