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shutvik [7]
4 years ago
15

Solve for x:4x-2>6x+8

Mathematics
1 answer:
xxTIMURxx [149]4 years ago
8 0

Answer:

The second option

Step-by-step explanation:

4x - 2 > 6x + 8

add 2 to both sides

4x - 2 + 2 > 6x + 8 + 2

2 cancel -2 and it remains

4x > 6x + 10

Now, subtract 6x from both sides

4x -6x > 6x -6x + 10

it remains

-2x > 10

divide via by -2

x > 10/-2

x < -5

When you multiply or divide by a negative, the inequality sign changes

Please mark as brainlest and have a good night.

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If a rectangle has an area of 36 square units, what could the dimensions be?
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6 0
4 years ago
The larger of two integers is 1 greater than twice the smaller integer the smaller integer is 17 less than twice the larger inte
horrorfan [7]
Larger = 2smaller + 1 ----(1)
smaller = 2 larger - 17 ----(2)

put (2) in (1)
larger = 2(2larger-17) + 1
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-3larger = - 33
so larger= 11
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3 0
4 years ago
4w + 13 = 81 | simplify your answer as much as possible
DochEvi [55]

Answer:

w = 17

Step-by-step explanation:

Isolate the variable, w. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Divisions

Additions

Subtractions

~

First, subtract 13 from both sides of the equation:

4w + 13 (-13) = 81 (-13)

4w = 81 - 13

4w = 68

Next, divide 4 from both sides of the equation:

(4w)/4 = (68)/4

w = 68/4

w = 17

w = 17 is your answer.

~

8 0
2 years ago
Read 2 more answers
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