D=mxv so your answer should be 269.37
no. The metal would be the hottest
Answer:
0.6 grams of hydrogen are needed to react with 2.75 g of nitrogen.
Explanation:
When hydrogen and nitrogen react they form ammonia.
Chemical equation:
N₂ + 3H₂ → 2NH₃
Given mass of nitrogen = 2.75 g
Number of moles of nitrogen:
Number of moles = mass/ molar mass
Number of moles = 2.75 g / 28 g/mol
Number of moles = 0.098 mol
Now we will compare the moles of nitrogen with hydrogen from balance chemical equation:
N₂ : H₂
1 : 3
0.098 : 3×0.098 = 0.3 mol
Mass of hydrogen:
Mass = number of moles × molar mass
Mass = 0.3 mol × 2 g/mol
Mass = 0.6 g
B and E are the answers I would choose.
On the left side, you have 2 nitrogen. On the right, you only have one. So put a 2 in front of the NH3. That gives you balanced nitrogen.
After that step, you have 6 hydrogen (the coefficient x the subscript) on the right, so you need to get 6 on the left. You have 2 hydrogen (subscript). 6/2 = 3, so put a coefficient of 3 in front of the H2, and you’ll have 6 hydrogen.
Your balanced equation is N2 + 3H2 -> 2NH3
Please lmk if you have questions.
Answer:
(S)−1−iodo−2−methylbutane
Explanation:
This reaction involves the substitution of iodine for bromine in (S)−1−bromo−2−methylbutane. The reaction proceeds with retention of configuration because the product is (S)−1−iodo−2−methylbutane. There is no change in the configuration of the product compound when the reaction is carried out in acetone which is a polar aprotic solvent. The reaction is shown in the image attached.
