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Andrew [12]
3 years ago
6

Definition of isotopes

Chemistry
2 answers:
sukhopar [10]3 years ago
5 0
Isotopes are atoms of the same element that have different numbers of neutrons.
klasskru [66]3 years ago
3 0
Isotopes are element that exhibits isotopy ie they have the same atomic no but different mass on
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For the reaction between aqueous silver nitrate and aqueous sodium chloride, write each of the following. The products of the re
vova2212 [387]

Answer:

A balanced ionic equation shows the reacting ions in a chemical reaction. These equations can be used to represent what happens in precipitation reactions or displacement reactions.

Precipitation reactions

In a typical precipitation reaction, two soluble reactants form an insoluble product and a soluble product.

For example, silver nitrate solution reacts with sodium chloride solution. Insoluble solid silver chloride and sodium nitrate solution form:

AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)

The Na+ ions and NO3- ions remain separate in the sodium nitrate solution and do not form a precipitate. Ions that remain essentially unchanged during a reaction are called spectator ions.This means these can be ignored when writing the ionic equation. Only how the solid silver chloride forms is needed to be shown:

Ag+(aq) + Cl-(aq) → AgCl(s)

In a balanced ionic equation:

the number of positive and negative charges is the same

the numbers of atoms of each element on the left and right are the same

Displacement reactions

Displacement reactions take place when a reactive element displaces a less reactive element from one of its compounds.

A common type of displacement reaction takes place when a reactive metal reacts with the salt of a less reactive metal. For example, copper reacts with silver nitrate solution to produce silver and copper(II) nitrate solution:

2AgNO3(aq) + Cu(s) → 2Ag(s) + Cu(NO3)2(aq)

In this reaction, the NO3- ions remain in the solution and do not react - they are the spectator ions in this reaction. So, they can be removed from the ionic equation:

2Ag+(aq) + Cu(s) → 2Ag(s) + Cu2+(aq)

Question

Explain why this ionic equation is balanced:

Ba2+(aq) + SO42-(aq) → BaSO4(s)

Hide answer

There are the same numbers of atoms of each element on both sides of the equation. The total charge on both sides is also the same (zero).

Question

Balance this ionic equation, which represents the formation of a silver carbonate precipitate:

Ag+(aq) + CO32-(aq) → Ag2CO3(s)

Hide answer

2Ag+(aq) + CO32-(aq) → Ag2CO3(s)

Question

Balance this ionic equation, which represents the displacement of iodine from iodide ions by chlorine:

Cl2(aq) + I-(aq) → I2(aq) + Cl-(aq)

Hide answer

Cl2(aq) + 2I-(aq) → I2(aq) + 2Cl-(aq

Explanation:

this will help, I used this for my work x

4 0
3 years ago
isotopes of an element have the same number of protons but a different number of neutrons below u will see the nucleus of four d
dexar [7]
What is your question? Its not clear
3 0
3 years ago
One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal
kenny6666 [7]

Answer:

Lithium oxide, Li₂O.  

Explanation:

Hello!  

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

M_2O+H_2\rightarrow 2M+H_2O  

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

5.00gM_2O*\frac{1molM_2O}{(2*X+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{XgM}{1molM}=2.32gM  

Thus, we perform the operations in order to obtain:

\frac{10X}{(2X+16)}=2.32  

So we solve for x as shown below:

10X=2.32(2X+16)\\\\10X=4.64X+37.12\\\\X=\frac{37.12}{10-4.64}\\\\X= 6.93g/mol  

Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.  

Best regards!

8 0
3 years ago
What happens to the length of a year for each planet as you get farther away from the sun
Bond [772]

Answer:

they get colder and darker, with less light

Explanation:

3 0
3 years ago
Convert 19 kcal into joules
il63 [147K]

19~ \text{kcal} = 19 \times 1000 ~\text{cal } = 19000~ \text{cal} = 19000 \times 4.184~ \text{J} = 79496~ \text{J}

7 0
2 years ago
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