Answer:
Step-by-step explanation:
( x , y ) ----> ( x - 1 , y ) ------> ( 2(x-1) , 2y ) = <em>( 2x - 2 , 2y )</em>
Answer:
inequality form: w<-1
interval notation: (-1)
if this is not what your looking for then this might help
53w+13<55w+16
get w to one side
subtract 53w from both sides
13<3w+16
get 3w by itself
subtract 16 from both sides
-3<3w
divided both side by 3 to solve for w
-1<w
or w>-1
i hope this helped
and if it helped plzzzz mark as brainlest im trying to level up thanks
Answer one, and it is correct.
Answer:
1,848
Step-by-step explanation:
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
