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zheka24 [161]
3 years ago
6

In an isolated system, Bicycle 1 and Bicycle 2, each with a mass of 10 kg,

Physics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer: 20 kgm/s

Explanation:

Given that M1 = M2 = 10kg

V1 = 5 m/s , V2 = 3 m/s

Since momentum is a vector quantity, the direction of the two object will be taken into consideration.

The magnitude of their combined

momentum before the crash will be:

M1V1 - M2V2

Substitute all the parameters into the formula

10 × 5 - 10 × 3

50 - 30

20 kgm/s

Therefore, the magnitude of their combined momentum before the crash will be 20 kgm/s

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Two astronauts, each with a mass of 50 kg, are connected by a 7 m massless rope. Initially they are rotating around their center
kiruha [24]

Answer:

The angular  velocity is w_f =  1.531 \ rad/ s

Explanation:

From the question we are told that

     The mass of each astronauts is  m =  50 \ kg

      The initial  distance between the two  astronauts  d_i  =  7 \  m

Generally the radius is mathematically represented as r_i  =  \frac{d_i}{2} = \frac{7}{2}  =  3.5 \  m

      The initial  angular velocity is  w_1 = 0.5 \  rad /s

       The  distance between the two astronauts after the rope is pulled is d_f =  4 \  m

Generally the radius is mathematically represented as r_f  =  \frac{d_f}{2} = \frac{4}{2}  =  2\  m

Generally from the law of angular momentum conservation we have that

           I_{k_1} w_{k_1}+ I_{p_1} w_{p_1} = I_{k_2} w_{k_2}+ I_{p_2} w_{p_2}

Here I_{k_1 } is the initial moment of inertia of the first astronauts which is equal to I_{p_1} the initial moment of inertia of the second astronauts  So

      I_{k_1} = I_{p_1 } =  m *  r_i^2

Also   w_{k_1 } is the initial angular velocity of the first astronauts which is equal to w_{p_1} the initial angular velocity of the second astronauts  So

      w_{k_1} =w_{p_1 } = w_1

Here I_{k_2 } is the final moment of inertia of the first astronauts which is equal to I_{p_2} the final moment of inertia of the second astronauts  So

      I_{k_2} = I_{p_2} =  m *  r_f^2

Also   w_{k_2 } is the final angular velocity of the first astronauts which is equal to w_{p_2} the  final angular velocity of the second astronauts  So

      w_{k_2} =w_{p_2 } = w_2

So

      mr_i^2 w_1 + mr_i^2 w_1 = mr_f^2 w_2 + mr_f^2 w_2

=>   2 mr_i^2 w_1 = 2 mr_f^2 w_2

=>   w_f =  \frac{2 * m * r_i^2 w_1}{2 * m *  r_f^2 }

=>    w_f =  \frac{3.5^2 *  0.5}{  2^2 }

=>   w_f =  1.531 \ rad/ s

       

3 0
3 years ago
An organism is composed of several organ systems. Often, the different organ systems work together towards a common purpose. For
Gemiola [76]

Answer:

Skeletal system, muscular system

Explanation:

Skeletal system:

bones

Muscular system:

muscles

Together, they work together and create the musculoskeletal system.

4 0
3 years ago
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What is the gravitational field theory and how does it work? four mark answer. Don't give me random answers just for points or i
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It is a theory on a show that people try to solve.
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2 years ago
The roof of a two-story house makes an angle of 29° with the horizontal. A ball rolling down the roof rolls off the edge at a sp
AlekseyPX

Answer:

t = 0.93 s

Part b)

d = 3.98 m

Part c)

v_x = 4.28 m/s

v_y = -11.49 m/s

Explanation:

The two components of the velocity of the ball is given as

v_x = 4.9 cos29

v_x = 4.28 m/s

v_y = 4.9 sin29

v_y = 2.37 m/s

Part a)

now we know that the displacement in y direction is given as

\Delta y = 6.4 m

so we have

\Delta y = v_y t + \frac{1}{2}gt^2

6.4 = 2.37 t + 4.9 t^2

t = 0.93 s

Part b)

Distance of the ball in x direction of the motion is given as

d = v_x t

d = 4.28 \times 0.93

d = 3.98 m

Part c)

In x direction the velocity will remain the same always

v_x = 4.28 m/s

while in Y direction we can use kinematics

v_y = v_{oy} + at

v_y = -2.37 - 9.81(0.93)

v_y = -11.49 m/s

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Which one of the following substances is a liquid fuel used in rocket engines?
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The substance which is a liquid fuel used in rocket engines is liquid oxygen. The correct answer is A.
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