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sergey [27]
2 years ago
8

A 65.0 kg skier slides down a 37.20 slope with mu = 0.107.What is the friction force?

Physics
1 answer:
zmey [24]2 years ago
3 0

Answer:

54.3N

Explanation:

The normal force is perpendicular to the slope, so:

Normal Force = cos(37.2)(9.8*65).......507.39N

F(friction)=mu*F(normal)

F(friction)=(0.107)(507.39)

F(friction)=54.3N

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Answer:

Explanation:

The most important thing to remember about parabolic motion in physics is that when an object reaches its max height, the velocity right there at the highest point is 0. Use this one-dimensional motion equation to solve this problem:

v = v₀ + at and filling in:

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The magnitude of the velocity vector of the car is ∣∣v→∣∣ = 78 ft/s. If the vector v→ forms an angle θ = 0.09 rad with the horiz
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Answer:

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Explanation:

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Since the angle θ and the magnitude of the velocity is given, the vector representation can be written as follows:

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