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sergey [27]
3 years ago
8

A 65.0 kg skier slides down a 37.20 slope with mu = 0.107.What is the friction force?

Physics
1 answer:
zmey [24]3 years ago
3 0

Answer:

54.3N

Explanation:

The normal force is perpendicular to the slope, so:

Normal Force = cos(37.2)(9.8*65).......507.39N

F(friction)=mu*F(normal)

F(friction)=(0.107)(507.39)

F(friction)=54.3N

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Answer:

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Explanation:

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What are the different isotopes
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Answer:

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3 years ago
A toaster uses 6700 joules of energy in 45 seconds to toast to a piece of bread what is power of the oven
just olya [345]
P= w/t and W= Work 
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si unit for Power is Watt (W) 
so, P= 6,700/45
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8 0
3 years ago
The fast train known as the TGV (Train à Grande Vitesse) that runs south from Paris, France, has a scheduled average speed of 21
andrezito [222]

Answer:

Explanation:

Given

average speed of train(v_{avg})=216 kmph\approx 60 m/s

Maximum acceleration=0.05g

Now centripetal acceleration is

a_c=\frac{v^2}{r}

0.05\times 9.8=\frac{60^2}{r}

r=7346.93 m

(b)Radius of curvature=900 m

therefore a_c=\frac{v^2}{r}

v=\sqrt{a_cr}

v=\sqrt{0.05\times 9.8\times 900}

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An astronaut weighs 863 N on Earth. What is the astronaut’s mass?
Alecsey [184]
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6 0
3 years ago
Read 2 more answers
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