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sergey [27]
3 years ago
8

A 65.0 kg skier slides down a 37.20 slope with mu = 0.107.What is the friction force?

Physics
1 answer:
zmey [24]3 years ago
3 0

Answer:

54.3N

Explanation:

The normal force is perpendicular to the slope, so:

Normal Force = cos(37.2)(9.8*65).......507.39N

F(friction)=mu*F(normal)

F(friction)=(0.107)(507.39)

F(friction)=54.3N

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A 40 Watt lightbulb is on for 3 minutes. How many joules of work does it do?
ella [17]

Answer:

Explanation:

Power (p)= 40 watt

time (t)= 3 minutes = 180 seconds

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E = 7200 Joules

Therefore it does 7200 joules of work.

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6 0
3 years ago
A young woman walks up 55 steps to the top of a water slide. She slides
navik [9.2K]

Answer:

potential energy PE = M g h

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Regardless of the slope of the slide the change in energy is the same

1/2 V^2 = g h

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5 0
2 years ago
PLEASE HELP!!!After a gas-filled balloon is released, it rises 90 feet by the end of the first minute. By the end of the second
fiasKO [112]
The situation is an example of an arithmetic progression through the data 90, 120, 150, .. . In this case, the arithmetic difference is 30. The expression that applies here is an = 90 + 30 * (n - 1) where n is the order of the term to be determined. If n is 8, then  the height is equal to a. 300 feet.
5 0
3 years ago
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Law Incorporation [45]

Answer:

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8 0
4 years ago
A spring with k = 53 N/m hangs vertically next to a ruler. The end of the spring is next to the 18 cm mark on the ruler. If a 2.
Anarel [89]

Answer:

1.07 m

Explanation:

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The spring line will end up at 1.07 m

4 0
3 years ago
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