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3 years ago

When a force is acting at axis of rotation,why torque is zero?

Physics

1 answer:

Vikki [24]3 years ago

4 0

Explanation:

see, torque=force × perpendicular distance

...that perpendicular distance is between axis of rotation and the point where force acts... so in above's case perpendicular distance is zero... so the torque is zero!

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I need help with this one ! <br><br>Explanation needed ~

weqwewe [10]

Answer:

Please find here some hints :

Rule. Newton’s second law, or fundamental principle of dynamics, mentions that a resultant force exerted on an object is always equal to the product of the mass of that object by its acceleration. ... Each force applied to an object causes this object to accelerate in the direction of the force applied.

Is acceleration a force?

The acceleration force, sometimes called the inertia force, is the vehicle’s resistance to speed variations. It holds you back when you increase your speed and pushes you back when you slow down.

Explanation:

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3 years ago

Observing neutrinos from the Sun is an important way to check the fusion rate, but it can be very tough to build a machine that

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Answer:

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3 years ago

A scientist performed an investigation involving a reaction that produce AI 2 (SO 4) 3 how many sulfur atoms are represented in

Korvikt [17]

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3 years ago

Read 2 more answers

A 70.0-kg person throws a 0.0430-kg snowball forward with a ground speed of 32.0 m/s. A second person, with a mass of 58.5 kg, c

Aleks04 [339]

Answer:

The velocities of the skaters are $v_{1} = 3.280\,\frac{m}{s}$ and $v_{2} = 0.024\,\frac{m}{s}$ , respectively.

Explanation:

Each skater is not under the influence of external forces during process, so that Principle of Momentum Conservation can be used on each skater:

First skater

$m_{1} \cdot v_{1, o} = m_{1} \cdot v_{1} + m_{b}\cdot v_{b}$ (1)

Second skater

$m_{b}\cdot v_{b} = (m_{2}+m_{b})\cdot v_{2}$ (2)

Where:

$m_{1}$ - Mass of the first skater, in kilograms.

$m_{2}$ - Mass of the second skater, in kilograms.

$v_{1,o}$ - Initial velocity of the first skater, in meters per second.

$v_{1}$ - Final velocity of the first skater, in meters per second.

$v_{b}$ - Launch velocity of the meter, in meters per second.

$v_{2}$ - Final velocity of the second skater, in meters per second.

If we know that $m_{1} = 70\,kg$ , $m_{b} = 0.043\,kg$ , $v_{b} = 32\,\frac{m}{s}$ , $m_{2} = 58.5\,kg$ and $v_{1,o} = 3.30\,\frac{m}{s}$ , then the velocities of the two people after the snowball is exchanged is: