The correct answer would be C. it moves at a constant speed. The troposphere(the layer our weather is in) is not nearly high enough for gravity to be different at different altitudes.
Answer:
1 is 90, 2 is 200 and 3 is 5
Explanation:
im big brain so i know lol
Answer:
a. A = 0.1656 m
b. % E = 1.219
Explanation:
Given
mB = 4.0 kg , mb = 50.0 g = 0.05 kg , u₁ = 150 m/s , k = 500 N / m
a.
To find the amplitude of the resulting SHM using conserver energy
ΔKe + ΔUg + ΔUs = 0
¹/₂ * m * v² - ¹/₂ * k * A² = 0
A = √ mB * vₓ² / k
vₓ = mb * u₁ / mb + mB
vₓ = 0.05 kg * 150 m / s / [0.050 + 4.0 ] kg = 1.8518
A = √ 4.0 kg * (1.852 m/s)² / (500 N / m)
A = 0.1656 m
b.
The percentage of kinetic energy
%E = Es / Ek
Es = ¹/₂ * k * A² = 500 N / m * 0.1656²m = 13.72 N*0.5
Ek = ¹/₂ * mb * v² = 0.05 kg * 150² m/s = 1125 N
% E = 13.72 / 1125 = 0.01219 *100
% E = 1.219
Answer A is incorrect
A crest is just one point. It is not the distance between 2 crests.
B is incorrect
A trough is just 1 point. It is not the distance between 2 troughs.
C is incorrect.
the amplitude measures the height of a crest from the middle of the wave to the crest (or trough).
D is the correct answer. That is the distance between 2 crests or 2 troughs
Answer:
7.2g
Explanation:
From the expression of latent heat of steam, we have
Heat supplied by steam = Heat gain water + Heat gain by calorimeter
mathematically,
+
=
+![m_{c}c_{c} \alpha c_{c}](https://tex.z-dn.net/?f=m_%7Bc%7Dc_%7Bc%7D%20%5Calpha%20c_%7Bc%7D%20)
L=specific latent heat of water(steam)=2268J/g
=specific heat capacity=4.2J/gK
=specific heat capacity of calorimeter =0.9J/gk
=280g
=38g
α=change in temperature
=(40-25)=15
=(40-25)=15
=(100-40)=60
Note: the temperature of the calorimeter is the temperature of it content.
From the equation, we can make
the subject of formula
![m_{s}=\frac{m_{w}c_{w} \alpha +m_{c}c_{c}\alpha}{c_{w}\alpha +l}](https://tex.z-dn.net/?f=m_%7Bs%7D%3D%5Cfrac%7Bm_%7Bw%7Dc_%7Bw%7D%20%5Calpha%20%2Bm_%7Bc%7Dc_%7Bc%7D%5Calpha%7D%7Bc_%7Bw%7D%5Calpha%20%2Bl%7D)
Hence
![m_{s}=\frac{(280*4.2*15) +(38*0.9*15)}{(4.2*60) +2268} \\m_{s}=\frac{18153}{2520}\\ m_{s}=7.2g](https://tex.z-dn.net/?f=m_%7Bs%7D%3D%5Cfrac%7B%28280%2A4.2%2A15%29%20%2B%2838%2A0.9%2A15%29%7D%7B%284.2%2A60%29%20%2B2268%7D%20%5C%5Cm_%7Bs%7D%3D%5Cfrac%7B18153%7D%7B2520%7D%5C%5C%20m_%7Bs%7D%3D7.2g)
Hence the amount of steam needed is 7.2g