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alexgriva [62]
3 years ago
14

A particle has 37.5 J of kinetic energy and 12.5 J of gravitational potential energy at one point during its fall from a tree to

the ground. An instant before striking the ground, how much mechanical energy-rounded to the nearest Joule-does the particle have? Ignore air resistance.​
Physics
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Answer: 50J

Explanation:

Mechanical energy follows the same principles of kinetic energy and potential energy, it is conserved. So Ei = Ef.

Mechanical energy is the sum of ALL energy's. There is no friction, so its just kinetic plus potential.

37.5 + 12.5 = 50J

Since the particle has not touched the ground, it has not transferred any energy to the ground yet, therefore the mechanical energy must still be 50J; mostly in kinetic energy with a very small amount of potential because of the low height relative to the ground.

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The overall length of a piccolo is 32.0 cm. The resonating air column vibrates as in a pipe that is open at both ends. (a) Find
lana66690 [7]

Answer:

lowest frequency = 535.93 Hz

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Explanation:

given data

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to find out

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solution

we consider here speed of sound through air at room temperature 20 degree is  approximately  v = 343 m/s

so

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lowest frequency will be = \frac{343}{2(0.32)}

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and

we have given highest frequency f = 4000Hz

so

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so distance =  \frac{wavelength}{2}   ..............3

distance =  \frac{0.08575}{2}  

distance = 0.0425 m

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3 years ago
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We will measure all angles from West, the negative x-axis and divide the journey into 3 parts:
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Overall displacement:
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Direction:
tan(∅) = y/x
∅ = tan⁻¹ (333 / 116)
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