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4 years ago

When an alkane reacts with an element from group 7a, the reaction is referred to as?

Chemistry

2 answers:

Mila [183]4 years ago

8 0

Answer:

Halogenation.

Explanation:

Hello,

In this case, we must remember that group VIIA elements are known as halogens which include F, Cl, Br, I and At. Now, when an alkane reacts with the diatomic form of one of those halogen a haloganation chemical reaction occurs forming an alkyl halide and a hydrogen halide. For instance, for ethane, if it reacts with iodine, ethyl iodide and hydrogen iodide are yielded based on the given example:

$CH_3-CH_3+I_2\rightarrow CH_3-CH_2-I+HI$

Best regards

Elena-2011 [213]4 years ago

7 0

Alkanes are saturated hydrocarbon, that is they contain hydrogen and carbon without a double or triple bond between the carbon atoms, e.g. ethane, propane. Group 7a in the periodic table are called halogens e.g chlorine, bromine. Alkanes react with halogens in a reaction called substitution, where halogens replace hydrogen atoms in alkanes.

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Answer:

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6 0

3 years ago

ethanol and benzene dissolve in each other. when ml of ethanol is dissolved in l of benzene, what is the mass of the mixture?

dsp73

The total mass of the mixture will be "958.5 g".

Calculation ,

According to the question, the density of both the mixtures will be:

Ethanol = 0.785 g/mL ( given )

Benzene = 0.880 g/mL ( given )

The volume of both the mixtures,

Ethanol = 100 mL ( given )

Benzene = 1.00 L or 1000 mL ( given )

As we know,

density = mass/volume

now,

The mass of Ethanol will be:

mass = density × volume = 0.785 g/mL × 100 mL

mass = 78.5 g

The mass of Benzene will be:

mass = density × volume = 0.880 g/mL × 1000 mL

mass = 880 g

hence,

The total mass of the mixture = 78.5 g + 880 g = 958.5 g

Missing data ,

density of Ethanol = 0.785 g/mL

density of Benzene = 0.880 g/mL

The volume of both the mixtures,

Ethanol = 100 mL

Benzene = 1.00 L

Learn more about mass of the mixture here:

brainly.com/question/15189339

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8 0

2 years ago

Assume that 8.5 L of iodine gas (I2) are produced at STP according to the following balanced equation:2KI(aq) + Cl2(

Aliun [14]

Answer: 0.3794 moles of Iodine gas are produced.

Explanation:

$2KI(aq)+Cl_2(
g)\rightarrow 2KCl(aq)+I_2$

Volume of iodine gas produced at STP =8.5 L

At STP, the 1 mol of gas occupies volume = 22.4 L

So, 8.5 L of volume will be occupied by: $\frac{1}{22.4 L}\times 8.5=0.3794 moles$

0.3794 moles of Iodine gas are produced.

5 0

3 years ago

Read 2 more answers

Density measurements were conducted on a 22.5oC sample of water which had a theoretical density of 0.997655 g/ml. A volume of 10

Sophie [7]

Let's divide the three experiments: The experiment with 10.00 mL of water is A), the experiment with 15.00 mL is B), and the experiment with 25.00 mL is C).

(1) Now let's calculate the experimental density of each experiment. Density (ρ) is equal to the mass divided by the volume, thus:

$p_{A} =9.98g/10.00mL=0.998g/mL\\p_{B} =15.61g/15.00mL=1.041g/mL\\p_{C} =25.65g/25.00mL=1.026g/mL$

(2)To calculate the average density, we add each density and divide the result by the number of experiments (in this case 3):

$p_{average}=\frac{p_{1}+p_{2}+p_{3}}{3} \\p_{average}=\frac{(0.998+1.041+1.026)g/mL}{3}\\p_{average}=1.022g/mL$

(3) The percent error is calculated by dividing the absolute value of the substraction of the theorethical and experimental values, by the theoretical value, times 100:

%error= $\frac{|p_{average}-p_{theoretical}|}{p_{theoretical}} *100$

%error= $\frac{|1.022g/mL-0.997655g/mL|}{0.997655g/mL}*100$

%error=2.44 %

7 0

3 years ago

What is a spectator ion?

Papessa [141]

<span>A spectator ion is an ion that exists in the same form on both the reactant and product sides of a chemical reaction.</span>

6 0

4 years ago

Read 2 more answers