<h3>Explanation:</h3>
1. PQ║TS, PQ ≅ TS, PT and QS are transversals to the parallel lines . . . given
2. ∠P ≅ ∠T . . . alternate interior angles at PT
3. ∠Q ≅ ∠S . . . alternate interior angles at QS
4. ΔPQR ≅ ΔTSR . . . ASA postulate
_____
You can use any pair of angles together with the sides PQ and TS. If you use the vertical angles and one of ∠T or ∠S, then you must invoke the AAS postulate for congruence, as the side is not between the two angles.
Answer:
a. Function 1
b. Function 3
c. Function 2, Function 3 and Function 4
Step-by-step explanation:
✔️Function 1:
y-intercept = -3 (the point where the line cuts across the y-axis)
Slope, using the two points (0, -3) and (1, 2):
Slope = 5
✔️Function 2:
y-intercept = -1 (the value of y when x = 0)
Slope, using the two points (0, -1) and (1, -4):
Slope = -3
✔️Function 3: y = 2x + 5
y-intercept (b) = 5
Slope (m) = 2
✔️Function 4:
y-intercept = 2
Slope = -1
Thus, the following conclusions can be made:
a. The function's graph that is steepest is the function whose absolute value of its slope is greater. Therefore Function 1 is the steepest with slope of 5
b. Function 3 has a y-intercept of 5, which is the farthest from 0.
c. Function 2, Function 3, and Function 4 all have y-intercept that is greater than -2.
-1, 5, and 2 are all greater than -2.
<span>The list of
scores will be: 30 60 63 65 65 67. To get the median, you have to
arrange the scores from lowest to highest. The middle number is the median. In
this, case there are two numbers in the middle so you have to add the two and
then divide by two.</span>
<span>Therefore, 63 +
65 = 128 / 2 = 64.</span>
Answer:
answer C
Hyperbolic geometry
The sum of the angles of a hyperbolic triangle is less than 180°.
Answer:
It has no solution because, 14x cancels out -14x when you move the variables to the left and leaves the equation as 0 = -12, however we know that 0 does not equal -12 which means this solution is false; therefore this equation has no solution since 0 does not equal -12.
Step-by-step explanation:
5 - 4x - 7 - 10x = -8x - 4 - 6x - 10 (Given)
-2 - 14x = -14x - 14 (Combine like terms)
0 = -12 (Move variables(x) to the left and the constants to the right)
