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Doss [256]
3 years ago
7

An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after

traveling a distance d. (a) What is the magnitude of the electric field? (Use any variable or symbol stated above along with the following as necessary: e for the charge of the electron.)
Physics
1 answer:
geniusboy [140]3 years ago
3 0

Answer:

E=\frac{K}{ed}

Explanation:

We are given that

Initial kinetic energy of an electron=K

Distance=d

Final velocity=v=0

Charge,q=-1e

We have to find the magnitude of electric field.

Work done=Force\times displacement

Using the formula

Work done=qE\times d=-eEd

Using work energy theorem

Work done=Final K.E-Initial K.E=0-K

Work done=-K

Substitute the values

-K=-eEd

K=eEd

E=\frac{K}{ed}

Hence, the magnitude of the electric field=E=\frac{K}{ed}

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How did the horizontal velocity vector component change during the flight of the cannonball in the simulation
arlik [135]

Answer:

<em>The horizontal velocity vector of the canonball does not change at all, but is constant throughout the flight.</em>

Explanation:

First, I'll assume this is a projectile simulation, since no simulation is shown here. That been the case, in a projectile flight, there is only a vertical component force (gravity) acting on the body, and no horizontal component force on the body. The effect of this on the canonball is that the vertical velocity component on the canonball goes from maximum to zero at a deceleration of 9.81 m/s^2, in the first half of the flight. And then zero to maximum at an acceleration of 9.81 m/s^2 for the second half of the flight before hitting the ground. <em>Since there is no force acting on the horizontal velocity vector of the canonball, there will be no acceleration or deceleration of the horizontal velocity component of the canonball. This means that the horizontal velocity component of the canonball is constant throughout the flight</em>

7 0
4 years ago
Determine the mass of the object below to the correct degree of precision.
OleMash [197]

Answer : The correct degree of precision is 272.94 g.

Explanation :

Precision : It is defined as the closeness of two or more measurements to each other.

For Example: If you weigh a given substance five times and you get 2.7 kg each time. Then the measurement is said to be precise.

Level of precision is determined by the maximum number of decimal places.

In the given figure, the value of mass of object is 280 g. From the given options we conclude that the 272.94 g is more close to 280 g and has maximum number of decimal places. So, 272.94 g measurement is said to be precise.

Therefore, the correct degree of precision is 272.94 g.

6 0
3 years ago
Your friend says the following to you: "The lungs are the main
posledela

The respiratory system is made up of multiple organs, saying that the lungs is the only required organ is very wrong. While the lungs are probably the most important part of it, the organs that transfer the air are definitely necessary for everything to work.

The main organ that is needed for air to flow from the mouth to the lungs is the trachea, or the windpipe. This connects the back of the mouth to the lungs, without this, no air could get into the lungs, thus rendering them useless.

7 0
4 years ago
If something is hot, does it contain heat or thermal energy?
zysi [14]
I am absolutely sure that if something is hot,  it contain thermal energy only because <span>if a given body is heated its electrons start to move very fast which means that thermal energy is being produced. Hope everything is clear! Regards!</span>
8 0
3 years ago
Two volumes of William Shakespeare stand on a bookshelf next to each other: volume one, then volume two. Each volume is 4 cm thi
Setler79 [48]

Answer:

L = 7 [cm]

Explanation:

To solve this problem we must analyze each of the distances mentioned and take into account the number of covers and thicknesses of these.

The worm crosses through the sheets of the first book, this distance can be determined by the following length analysis.

4 = P + 2*C

Where:

P = thicknesses of the pages [cm]

C = thicknesses of each cover [cm]

P = 4 - 2*(0.5)

P = 3 [cm]

The distance crossed was:

L = P + 2C + P "the pages of the first book + 2 covers + the pages of the second book"

L = 3 + (2*0.5) + 3

L = 7 [cm]

7 0
3 years ago
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