An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after
1 answer:
Answer:
Explanation:
We are given that
Initial kinetic energy of an electron=K
Distance=d
Final velocity=v=0
Charge,q=-1e
We have to find the magnitude of electric field.
Work done=
Using the formula
Work done=
Using work energy theorem
Work done=Final K.E-Initial K.E=0-K
Work done=-K
Substitute the values
-K=-eEd
K=eEd
Hence, the magnitude of the electric field=
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Answer:
Approximately , assuming friction between the vehicle and the ground is negligible.
Explanation:
Let denote the mass of the vehicle. Let
denote the initial velocity of the vehicle. Let
denote the spring constant (needs to be found.) Let
denote the maximum displacement of the spring.
Convert velocity of the vehicle to standard units (meters per second):
.
Initial kinetic energy () of the vehicle:
.
When the vehicle is brought to a rest, the elastic potential energy () stored in the spring would be:
.
By the conservation of energy, if the friction between the vehicle and the ground is negligible, the initial of the vehicle should be equal to the
of the vehicle. In other words:
.
Rearrange this equation to find an expression for , the spring constant:
.
Substitute in the given values ,
, and
: