Ask question

Ask question

All categories

Harlamova29_29 [7]

3 years ago

11

Rocks that fall out of the sky and land on Earth are called _____________. Question 7 options: A.meteorites B.asteroids C.comets

D.meteors

2 answers:

kenny6666 [7]3 years ago

3 0

They’re called meteorites

julsineya [31]3 years ago

3 0

They’re called meteorites

You might be interested in

Which type of acceleration would be best if you were merging onto the interstate?

kondaur [170]

Answer:

If merging onto an interstate, it is best to merge at the speed of the moving traffic.

Explanation:

As a driver, you cannot always count on the other drivers to see you wanting to merge onto the interstate, and even if they see you, they might not be willing to stop just so you merge, therefore it is best advised to look for a gap in the traffic and merge at the traffic speed.

4 0

3 years ago

1. Acceleration can result from a change of _______, or a change in ___________, or both *

Klio2033 [76]

Answer:

not sure

Explanation:

jahhhhhsjjjjdddddhdhdj hbdbd#dialectical DHL I have no clue W Bush administration and I don't have any jshshhhhdgggddddddd the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

jsbsbd the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

BFF and I don't have any questions please call her and her husband to the hospital for a bit more time with my family grew up in the form of a ring whose inner circumference is it a lot of people who are you doing today beautiful and I don't have any questions please call her and her husband to the

4 0

3 years ago

A point charge +2Q is at the origin and a point charge −Q is located along the x axis at x = d as in the figure below. Find a sy

Akimi4 [234]

Answer: A symbolic expression for the net force on a third point charge +Q located along the y axis

$F_N=k_e\frac{Q^2}{d^2}\times \sqrt{[4+\frac{1}{4}-\sqrt{2}]}$

Explanation:

Let the force on +Q charge y-axis due to +2Q charge be $F_1$ and force on +Q charge y axis due to -Q charge on x-axis be $F_2$ .

Distance between the +2Q charge and +Q charge = d units

Distance between the -Q charge and +Q charge = $\sqrt{2}d$ units

$k_e$ = Coulomb constant

$F_1=k_e\frac{(+2Q)(+Q)}{d^2}=k_e\frac{+2Q^2}{d^2} N$

$F_2=k_e\frac{(-Q)(+Q)}{(\sqrt{2}d)^2}=k_e\frac{-Q^2}{2d^2} N$

Net force on +Q charge on y-axis is:

$F_x=F_2sin 45^o=k_e\frac{-Q^2}{2d^2}\times \frac{1}{\sqrt{2}} N$

$F_y=F_1-F_2cos45^o$

$F_y=(F_1-F_2cos45^o)=(k_e\frac{+2Q^2}{d^2})-(k_e\frac{-Q^2}{2d^2}\frac{1}{\sqrt{2}})$

$F_N=\sqrt{F_x^2+F_y^2}$

$|F_N|=|k_e\frac{Q^2}{d^2}\times \sqrt{[4+\frac{1}{4}-\sqrt{2}]}|$

The net froce on the +Q charge on y-axis is

$F_N=k_e\frac{Q^2}{d^2}\times \sqrt{[4+\frac{1}{4}-\sqrt{2}]}$

4 0

3 years ago

Read 2 more answers

Which of the following is a true statement about learning?

Furkat [3]

Answer:

B. learning happens through experience and practice.

3 0

3 years ago

Please help!! I'm stuck on this, could someone also explain if they can!! Will give brainiest if I can!!

Ann [662]

The answer is going to be c. hope that helped

8 0

3 years ago