The x -component of the object's acceleration is 2 m/s².
<h3>What's the resultant force along x- direction?</h3>
- Forces along x axis direction are as follows
- 4N along +x axis, so it's taken as +4 N
- 2N along -x axis , so it's taken as -2N.
- Resultant force along x direction = 4N - 2N = 2 N which is along + ve x direction.
<h3>What's the acceleration along x axis direction?</h3>
- As per Newton's second law, Force = mass × acceleration of the object
- Force along x axis= mass × acceleration along x axis= 2N
- Acceleration = 2/ mass = 2/1 = 2 m/s²
Thus, we can conclude that the acceleration along x axis is 2 m/s².
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The forces in (Figure 1) are acting on a 1.0 kg object. What is ax, the x-component of the object's acceleration?
Learn more about the acceleration here:
brainly.com/question/460763
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Scalar Quantity :-
→ These are the quantities with magnitude only . These quantities doesn't have to be mentioned with direction
eg.)=> Mass , Temprature .
Vector Quantity :-
→ These quantities are described with both Magnitude and Direction . These quantities follow special type of algebra called Vector algebra .
eg.)=> Force , Displacement
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Hope It Helps You. ☺
Answer:
D. 160 nm
Explanation:
The energy released from n = 3 to n = 1 must be equal to the sum of energies released from n = 3 to n = 2 and from n = 2 to n = 1. Therefore,
Energy of Photon from 3 to 1 = Energy of Photon from 3 to 2 + Energy of Photon from 2 to 1
![\frac{hc}{\lambda} = \frac{hc}{\lambda_{1}} + \frac{hc}{\lambda_{2}}\\\\\frac{1}{\lambda} = \frac{1}{\lambda_{1}} + \frac{1}{\lambda_{2}}](https://tex.z-dn.net/?f=%5Cfrac%7Bhc%7D%7B%5Clambda%7D%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda_%7B1%7D%7D%20%2B%20%5Cfrac%7Bhc%7D%7B%5Clambda_%7B2%7D%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%20%5Cfrac%7B1%7D%7B%5Clambda_%7B1%7D%7D%20%2B%20%5Cfrac%7B1%7D%7B%5Clambda_%7B2%7D%7D)
where,
λ = wavelength of photon released from 3 to 1 = ?
λ₁ = wavelength of photon released from 3 to 2 = 800 nm
λ₂ = wavelength of photon released from 2 to 1 = 200 nm
Therefore,
![\frac{1}{\lambda} = \frac{1}{800\ nm} + \frac{1}{200\ nm}\\\\\frac{1}{\lambda} = 0.00625 nm^{-1}\\\\\lambda = \frac{1}{0.00625 nm^{-1}}\\\\\lambda = 160 nm](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%20%5Cfrac%7B1%7D%7B800%5C%20nm%7D%20%2B%20%5Cfrac%7B1%7D%7B200%5C%20nm%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3D%200.00625%20nm%5E%7B-1%7D%5C%5C%5C%5C%5Clambda%20%3D%20%5Cfrac%7B1%7D%7B0.00625%20nm%5E%7B-1%7D%7D%5C%5C%5C%5C%5Clambda%20%3D%20160%20nm)
Therefore, the correct option is:
<u>D. 160 nm</u>