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2 years ago

All of the following are examples of suspensions except:

2 answers:

4 0

Salt water is not an example of suspension as salt dissolves in water and combines with it rather than float in the water.

Lorico [155]2 years ago

4 0

The answer is

-dust particles in the air
proof
all the three are eatable exept D

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If a toy has a mass of 1 kg, it has an Earth weight of

marshall27 [118]

Answer:

The answer is 9.8 N

Explanation:

As we know that the weight of an object is the amount of gravitational force acting on the object in an upward direction if the weight is acting is the downward direction.

The formula of weight:

W = Mass x Gravitational force

W = m x g

Given data:

Mass =1 kg

g = 9.8 ms-2

W = 1kg x 9.8 ms-2 = 9.8 kgms-2 ( 1 kgms-2 = N)

SO,

W = 9.8 N

The toy has an earth weight of 9.8 N.

4 0

3 years ago

The process of making alloys involves(Cooling, Heating or mixing) pure metals to remove impurities. Then the pure metals are(bro

ANEK [815]

The process of making alloys involves ( Heating ) pure metals to remove impurities. Then the pure metals are(mixed) with other components. An alloy is a mixture of metals or a mixture of a metal and another element. Alloys are defined by a metallic bonding character.

8 0

2 years ago

Read 2 more answers

On a certain planet, which is perfectly spherically symmetric, the free-fall acceleration has magnitude g = go at the north pole

ohaa [14]

The reason why there is a difference between free-fall acceleration is a centrifugal force.
I attached a diagram that shows how this force aligns with the force of gravity.
From the diagram we can see that:
$F=F_g-F_{cf}=mg'-mw^2r'cos(\alpha)\\ ma=mg'-mw^2r'cos(\alpha)\\ a=g'-w^2rcos^2(\alpha)\\$
Where g' is the free-fall acceleration when there is no centrifugal force, r is the radius of the planet, and w is angular frequency of planet's rotation. $\alpha$ is the latitude.
We can calculate g' and wr^2 from the given conditions in the problem.
$g(90)=g_0;\ g_0= g'-w^2rcos^2(90)\\
g_0=g'\\
g(0)=ag_0;\ ag_0=g_0-w^2rcos^2(0)\\
ag_0=g_0-w^2r\\
w^2r=g_0(a-1)
$
Our final equation is:
$g=g_0-g_0(a-1)cos^2(\alpha)$
Colatitude is:
$\alpha_c=90^\circ-\alpha$
The answer is:
$g=g_0-g_0(a-1)cos^2(90-9)=g_0-g_0(a-1)sin^2(9)$

5 0

3 years ago

An experiment is performed to test the effect of three different types of water on the growth of a plant. The test is done by us

natima [27]

I think the correct answer would be D. The tap water in the experiment is one the three test conditions of the independent variable, the type of water. The independent variable in a experiment is the one being manipulated or the one being changed. In this case, it is the type of water.

6 0

3 years ago

Read 2 more answers

Consider the following cyclic process carried out in two steps on a gas. Step 1: 44 J of heat is added to the gas, and 20. J of

notka56 [123]

Answer:37 J

Explanation:

Given

Step :1

Heat added Q=44 J

Work done=-20 J

$\Delta E_1=Q+W=44-20=24 J$