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makkiz [27]
3 years ago
7

Which of the following is a single replacement reaction?

Chemistry
1 answer:
prohojiy [21]3 years ago
3 0

The correct answer is option d, that is, Zn + H₂SO₄ → ZnSO₄ + H₂

A single displacement reaction refers to a kind of chemical reaction in which one element substitutes another element in a chemical reaction. The more reactive element will substitute the less reactive element. This is illustrated with the help of reactivity series, as the metal that is present above in the series will substitute the metal that is present below in the series readily. From the given equations, Zn + H₂SO₄ → ZnSO₄ + H₂ is a kind of single displacement reaction.  


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Nucleic Acids are polymers made of nucleotideds 
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3 years ago
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What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)?
vova2212 [387]
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6 0
2 years ago
Polonium is a rare element with 33 radioisotopes. The most common one, 210Po, has 84 protons and 126 neutrons. When 210Po decays
Fofino [41]

Answer:

Lead Pb

Explanation:

Firstly, we need to know what occurs when a radioisotope emits an alpha particle. An alpha particle is an helium atom. When an isotope emits an alpha particle, it loses an helium atom corresponding to subtracting 4 from its mass number and 2 from its atomic number. This of course coupled with the release of radiation.

Now, we polonium has a proton number of 84 and a mass number of 210. Subtracting 2 and 4 respectively from its proton and mass numbers will yield 82 and 206 proton and mass numbers respectively.

Hence, the decomposition of the Po-210 isotope will yield an element with 82 proton number and 206 mass number. This corresponds to the element Lead.

210Po ——> 206Pb + alpha particle + radiation

6 0
2 years ago
Consider the reaction of ruthenium(III) iodide with carbon dioxide and silver. RuI3 (s) 5CO (g) 3Ag (s) Ru(CO)5 (s) 3AgI (s) Det
mixer [17]

Answer:

71.6 g of Ru(CO)₅ is the maximum mass that can be formed.

The limiting reactant is Ag

Explanation:

The reaction is:

RuI₃ (s) + 5CO (g) + 3Ag (s) → Ru(CO)₅ (s) + 3AgI (s)

Firstly we determine the moles of each reactant:

169 g . 1mol /481.77g = 0.351 moles of RuI₃

58g . 1mol /28g = 2.07 moles of CO

96.2g . 1mol/ 107.87g = 0.892 moles

Certainly, the excess reactant is CO, therefore, the limiting would be Ag or RuI₃.

3 moles of Ag react to 1 mol of RuI₃

Then 0.892 moles of Ag may react to (0.892 . 1) /3 = 0.297 moles

We have 0.351 moles of iodide and we need 0.297 moles, so this is an excess. In conclussion, Silver (Ag) is the limiting.

1 mol of RuI₃ react to 3 moles of Ag

Then, 0.351 moles of RuI₃ may react to (0.351 . 3) /1 = 1.053 moles

It's ok, because we do not have enough Ag. We only have 0.892 moles and we need 1.053.

5 moles of CO react to 3 moles of Ag

Then, 2.07 moles of CO may react to (2.07 . 3) /5 = 1.242 moles of Ag.

This calculate confirms the theory.

Now, we determine the maximum mass of Ru(CO)₅

3 moles of of Ag can produce 1 mol of Ru(CO)₅

Then 0.892 moles may produce (0.892 . 1) /3 = 0.297 moles

We convert moles to mass → 0.297 mol . 241.07g /mol = 71.6 g

8 0
3 years ago
Which change in this process would shift the equilibrium to produce the
vampirchik [111]

Answer: B I think, I'll put my reasoning below.

Explanation:

It's not A because removing N2 would only shift the equation the opposite way.

It's not C and D because I don't think those affect the specific amount of each reactant/product produced. I think temperature only affects the speed at which the reaction is performed, which won't affect anything in this case.

7 0
2 years ago
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