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oksian1 [2.3K]
3 years ago
14

In the nucleus of an atom, two protons are separated are by a distance of 1*10^-15m. What is the magnitude of the electric force

between them?
A. 115N
B. 720N
C. 142N
D. 230N
Physics
1 answer:
xenn [34]3 years ago
4 0

Answer:

D. 230 N

Explanation:

The magnitude of the electric force between the two protons is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q_1 = q_2 = 1.6\cdot 10^{-19} C is the charge of each proton

r=1\cdot 10^{-15} m is the distance between the two protons

Substituting numbers into the formula, we find

F=(9\cdot 10^9 N m^2 C^{-2}) \frac{(1.6\cdot 10^{-19} C)^2}{(1\cdot 10^{-15} m^2)^2}=230.4 N \sim 230 N

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Which element has 19 electrons surrounding the nuclei of its atoms?
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I think it's potassium, but i'm not sure
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A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma
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Incomplete question as we have not told to find what.So the complete question is here

A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of mass m, moves with velocity (-60 m/s)i and a second piece, also of mass m, moves with velocity (-60 m/s)j. The third piece has mass 3m.Just after the explosion, what are the (a) magnitude and (b) direction of the velocity of the third piece?

Answer:

V_{3}=(20i+20j)m/s

Explanation:

Given data

The vessel at rest

Piece one,of mass m,moves with velocity=(-60 m/s)i

Piece two,of mass m,moves with velocity=(-60 m/s)j

Piece three,of mass 3m

As the linear momentum is conserved in this system,Because the system is closed and no external  force acting on it

So momentum is given as

p_{initial}=p_{final}

As the vessel at rest so the initial momentum is zero

So

m_{1}V_{1}+m_{2}V_{2}+m_{3}V_{3}=0\\m_{3}V_{3}=-m_{1}V_{1}-m_{2}V_{2}\\V_{3}=\frac{-m_{1}V_{1}-m_{2}V_{2}}{m_{3}} \\V_{3}=\frac{-m_{1}(-60m/s)i-m_{2}(-60m/s)j}{3m}\\V_{3}=(20i+20j)m/s

 

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3 years ago
G How much buoyancy force, in N, a person with a mass of 70 kg experiences by just standing in air
sattari [20]

Answer:

686.7N

Explanation:

Given data

Mass= 70kg

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Weight = mass* Acceleration

Weight= 70*9.81

Weight= 686.7N

Therefore the weight is 686.7N

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3 years ago
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