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oksian1 [2.3K]
3 years ago
14

In the nucleus of an atom, two protons are separated are by a distance of 1*10^-15m. What is the magnitude of the electric force

between them?
A. 115N
B. 720N
C. 142N
D. 230N
Physics
1 answer:
xenn [34]3 years ago
4 0

Answer:

D. 230 N

Explanation:

The magnitude of the electric force between the two protons is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q_1 = q_2 = 1.6\cdot 10^{-19} C is the charge of each proton

r=1\cdot 10^{-15} m is the distance between the two protons

Substituting numbers into the formula, we find

F=(9\cdot 10^9 N m^2 C^{-2}) \frac{(1.6\cdot 10^{-19} C)^2}{(1\cdot 10^{-15} m^2)^2}=230.4 N \sim 230 N

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Answer:

The force between the Earth and the object is, F = 9.61 x 10⁻¹² N

Explanation:

Given data,

The mass of the Earth, M = 5.9 x 10²⁴ kg

The mass of the object, m = 10 kg

The gravitational force between the earth and the object is given by the formula,

                         F = G Mm/R²

Substituting the given values in the above equation,

                         F = 6.673 x 10⁻¹¹ x 5.9 x 10²⁴ x 10 / 6.4 x 10⁶

                            =  9.61 x 10⁻¹² N

Hence, the force between the Earth and the object is, F = 9.61 x 10⁻¹² N

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When a neutral atom looses an electron to another neutral atom, two charged atoms are created.

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A driver who does not wear a seatbelt continues to move forward with a speed of 18.0 m/s (due to inertia) until something solid
vredina [299]

Answer:

F = 2.113 x 10⁵ N

Explanation:

First we need to calculate the deceleration of the driver by using 3rd equation of motion:

2as = Vf² - Vi²

where,

a = deceleration = ?

s = distance = 5 cm = 0.05 m

Vf = Final Velocity = 0 m/s

Vi = Initial Velocity = 18 m/s

Therefore,

2a(0.05 m) = (0 m/s)² - (18 m/s)²

a = (- 324 m²/s²)/0.1 m

a = - 3240 m/s²

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From Newton's Second Law of Motion:

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