Answer:
a)N = 3.125 * 10¹¹
b) I(avg) = 2.5 × 10⁻⁵A
c)P(avg) = 1250W
d)P = 2.5 × 10⁷W
Explanation:
Given that,
pulse current is 0.50 A
duration of pulse Δt = 0.1 × 10⁻⁶s
a) The number of particles equal to the amount of charge in a single pulse divided by the charge of a single particles
N = Δq/e
charge is given by Δq = IΔt
so,
N = IΔt / e
![N = \frac{(0.5)(0.1 * 10^-^6)}{(1.6 * 10^-^1^9)} \\= 3.125 * 10^1^1](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B%280.5%29%280.1%20%2A%2010%5E-%5E6%29%7D%7B%281.6%20%2A%2010%5E-%5E1%5E9%29%7D%20%5C%5C%3D%203.125%20%2A%2010%5E1%5E1)
N = 3.125 * 10¹¹
b) Q = nqt
where q is the charge of 1puse
n = number of pulse
the average current is given as I(avg) = Q/t
I(avg) = nq
I(avg) = nIΔt
= (500)(0.5)(0.1 × 10⁻⁶)
= 2.5 × 10⁻⁵A
C) If the electrons are accelerated to an energy of 50 MeV, the acceleration voltage must,
eV = K
V = K/e
the power is given by
P = IV
P(avg) = I(avg)K / e
![P(avg) = \frac{(2.5 * 10^-^5)(50 * 10^6 . 1.6 * 10^-^1^9)}{1.6 * 10^-^1^9}](https://tex.z-dn.net/?f=P%28avg%29%20%3D%20%5Cfrac%7B%282.5%20%2A%2010%5E-%5E5%29%2850%20%2A%2010%5E6%20.%201.6%20%2A%2010%5E-%5E1%5E9%29%7D%7B1.6%20%2A%2010%5E-%5E1%5E9%7D)
= 1250W
d) Final peak=
P= Ik/e
= ![= P(avg) = \frac{(0.5)(50 * 10^6 . 1.6 * 10^-^1^9)}{1.6 * 10^-^1^9}\\2.5 * 10^7W](https://tex.z-dn.net/?f=%3D%20P%28avg%29%20%3D%20%5Cfrac%7B%280.5%29%2850%20%2A%2010%5E6%20.%201.6%20%2A%2010%5E-%5E1%5E9%29%7D%7B1.6%20%2A%2010%5E-%5E1%5E9%7D%5C%5C2.5%20%2A%2010%5E7W)
P = 2.5 × 10⁷W
Explanation:
It is known that wave intensity is the power to area ratio.
Mathematically, I = ![\frac{P}{A}](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7BA%7D)
As it is given that power is 28.0 W and area is
.
Therefore, sound intensity will be calculated as follows.
I = ![\frac{P}{A}](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7BA%7D)
= ![\frac{28.0 W}{4 \times 3.14 \times 7 \times 10^{-5} m^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B28.0%20W%7D%7B4%20%5Ctimes%203.14%20%5Ctimes%207%20%5Ctimes%2010%5E%7B-5%7D%20m%5E%7B2%7D%7D)
= ![0.318 \times 10^{5} W/m^{2}](https://tex.z-dn.net/?f=0.318%20%5Ctimes%2010%5E%7B5%7D%20W%2Fm%5E%7B2%7D)
or, = ![3.18 \times 10^{4} W/m^{2}](https://tex.z-dn.net/?f=3.18%20%5Ctimes%2010%5E%7B4%7D%20W%2Fm%5E%7B2%7D)
Thus, we can conclude that sound intensity at the position of the microphone is
.
The plant that is closest to the sun is murcury. Then it is venus, then earth, and then mars. Then it is jupiter, then saturn, then uranus, then neptune.
Answer:
3.5m/s^2
Explanation:
From Newton's second Law of Motion
F = ma
Where F is the applied force, m is the mass of the object and a is the acceleration.
F = 350 N
Mass = 100kg
350N = 100×a
a = 350/100
a = 3.5m/s^2
The acceleration of the object will be 3.5m/s^2
Answer:
final velocity will be44.72m/s
Explanation:
HEIGHT=h=100m
vi=0m/s
vf=?
g=10m/s²
by using third equation of motion for bodies under gravity
2gh=(vf)²-(vi)²
evaluating the formula
2(10m/s²)(100m)=vf²-(0m/s)²
2000m²/s²=vf²
√2000m²/s²=√vf²
44.72m/s=vf