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Juli2301 [7.4K]
3 years ago
9

A hydrogen atom that has an electron in the n = 2 state absorbs a photon. What wavelength must the photon possess to send the el

ectron to the n = 4 state?
Physics
1 answer:
Deffense [45]3 years ago
4 0

Answer:

486nm

Explanation:

in order for an electron to transit from one level to another, the wavelength emitted is given by Rydberg Equation which states that

\frac{1}{wavelength}=R.[\frac{1}{n_{f}^{2} } -\frac{1}{n_{i}^{2} }] \\n_{f}=2\\n_{i}=4\\R=Rydberg constant =1.097*10^{7}m^{-1}\\subtitiute \\\frac{1}{wavelength}=1.097*10^{7}[\frac{1}{2^{2} } -\frac{1}{4^{2}}]\\\frac{1}{wavelength}= 1.097*10^{7}*0.1875\\\frac{1}{wavelength}= 2.06*10^{6}\\wavelength=4.86*10{-7}m\\wavelength= 486nm\\

Hence the photon must possess a wavelength of 486nm in order to send the electron to the n=4 state

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