Answer:
The Roche limit for the Moon orbiting the Earth is 2.86 times radius of Earth
Explanation:
The nearest distance between the planet and its satellite at where the planets gravitational pull does not torn apart the planets satellite is known as Roche limit.
The relation to determine Roche limit is:
![Roche\ limit=2.423\times R_{P}\times\sqrt[3]{\frac{D_{P} }{D_{M} } }](https://tex.z-dn.net/?f=Roche%5C%20limit%3D2.423%5Ctimes%20R_%7BP%7D%5Ctimes%5Csqrt%5B3%5D%7B%5Cfrac%7BD_%7BP%7D%20%7D%7BD_%7BM%7D%20%7D%20%7D)
....(1)
Here 
is radius of planet and 
are density of planet and moon respectively.
According to the problem,
Density of Earth,
= 5.5 g/cm³
Density of Moon,
= 3.34 g/cm³
Consider 
be the radius of the Earth.
Substitute the suitable values in the equation (1).
![Roche\ limit=2.423\times R_{E}\times\sqrt[3]{\frac{5.5 }{3.34 } }](https://tex.z-dn.net/?f=Roche%5C%20limit%3D2.423%5Ctimes%20R_%7BE%7D%5Ctimes%5Csqrt%5B3%5D%7B%5Cfrac%7B5.5%20%7D%7B3.34%20%7D%20%7D)
1: Lost (?)
2: Space (?)
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<span>Sound travels fastest through solids, slower through liquids and slowest through gases.
Answer: Cast Iron, D.
</span>
After one day, the rate of increase in Delta Cephei's brightness is;0.46
We are informed that the function has been used to model the brightness of the star known as Delta Cephei at time t, where t is expressed in days;
B(t)=4.0+3.5 sin(2πt/5.4)
Simply said, in order to determine the rate of increase, we must determine the derivative of the function that provides
B'(t)=(2π/5.4)×0.35 cos(2πt/5.4)
Currently, at t = 1, we have;
B'(1)=(2π/5.4)×0.35 cos(2π*1/5.4)
Now that the angle in the bracket is expressed in radians, we can use a radians calculator to determine its cosine, giving us the following results:
B'(1)=(2π/5.4)×0.3961
B'(1)≈0.46
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If you are given time and distance, you can determine power if you know
force. watts. energy. joules.
Answer is joules.
Power is defined as the rate of
doing work. Hence power = work / time then you obtain watts. Work is the
product of force and displacement (distance). Hence in formula, w = F x s. In
which the S.I unit of work is joule in the product. This is what you have to
obtain in order to calculate for power.
