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cestrela7 [59]
3 years ago
7

Which trial’s cart has the greatest momentum at the bottom of the ramp?

Physics
1 answer:
Licemer1 [7]3 years ago
8 0
The momentum of each cart is given by:
p=mv
where
m is the mass of the cart
v is its velocity (at the bottom of the ramp)

To answer the problem, let's calculate the momentum of each of the 4 carts:
1) p=(200 kg)(6.5 m/s)=1300 kg m/s
2) p=(220 kg)(5.0 m/s)=1100 kg m/s
3) p=(240 kg)(6.4 m/s)= 1536 kg m/s
4) p=(260 kg)(4.8 m/s)=1248 kg m/s

Therefore, the cart with greatest momentum is cart 3, so the right answer is
<span>- trial 3, because this trial has a large mass and a large velocity</span>
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