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White raven [17]
3 years ago
10

Help me with this please ​

Chemistry
1 answer:
Gala2k [10]3 years ago
8 0

Answer:

Gap 1, S-Phase, Gap 2, Prophase, Metaphase, Anaphase, Telophase, Cytokinesis

Hope this helps.

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A 1.26-g sample of an alkaline earth metal chloride is treated with excess silver nitrate. All of the chloride is recovered as 3
erastova [34]

Answer:

The metal is calcium (to form CaCl2)

Explanation:

Step 1: Data given

Mass of sample of an alkaline earth metal chloride = 1.26 grams

Silvernitrate (AgNO3) = in excess

All of the chloride is recovered as 3.26 g of silver chloride.

Step 2: The equation

XCl2 + 2AgNO3 → X(NO3)2+ 2 AgCl

Step 3: Calculate moles AgCl

Moles AgCl = mass AgCl / molar mass AgCl

Moles AgCl = 3.26 grams / 143.32 g/mol

Moles AgCl = 0.0227 moles

Step 4: Calculate moles XCl2

For 1 mol XCl2 we'll have 2 moles AgCl

For 2*0.0227 moles we need 0.0227/2 = 0.01135 moles

Step 5: Calculate molar mass XCl2

Molar mass XCl2 = mass / moles XCl2

Molar mass XCl2 = 1.26 grams / 0.01135 moles

Molar mass XCl2 = 111 g/mol

Step 6: Calculate of metal X

Molar mass X = molar mass XCl2 - molar mass Cl2

Molar mass X = 111 - 70.9 = 40.1 g/mol

The metal is calcium (to form CaCl2)

5 0
3 years ago
Predict the chemical formula of the compound that will form when Li and o interact.
Ksivusya [100]

Answer:

Li_2O

Explanation:

Hello!

In this case, when looking over the chemical formula of a compound formed when two elements interact, we need to realize about their location in the periodic table; thus, since lithium is a metal and oxygen a nonmetal, we infer lithium turns out the cation and oxygen the anion. Moreover, as the oxidation state of lithium is 1+ and that of oxygen is 2-, we can set up the chemical formula as follows:

Li^+O^{2-}\\\\Li_2O

Best regards!

4 0
2 years ago
Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
9966 [12]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

5 0
3 years ago
The bottom number on the periodic table is called?
salantis [7]

Answer:

The atomic number that should be here, 57, is located at the bottom of the table in the row called the Lanthanides. Directly below the space in Row 6, in Row 7, is another empty space, which is filled by a row called the Actinides, also seen at the bottom of the chart.

Explanation:

hope this helps!

8 0
3 years ago
The radius of a helium atom is a 31 PM. What is the radius in nanometers?
Paladinen [302]

Answer:

Thus, the radius of the helium atom in nanometers is - 0.031 nm

Explanation:

Given that:-

The radius of the helium atom = 31 pm

Considering the conversion of length in pm to the length in nm as:-

1 pm = 0.001 nm

So,

Applying the above conversion factor in the radius of helium atom as:-

Radius = 31\times 0.001 nm = 0.031 nm

<u>Thus, the radius of the helium atom in nanometers is - 0.031 nm</u>

7 0
3 years ago
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