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SVETLANKA909090 [29]
3 years ago
11

Save-way-more food store received  a delivery of 86 boxes of apples and bananas. Each box of apples had a mass of 32 Ib., and ea

ch box of bananas had a mass of 16 Ib. The total mass of the delivery was 1968 Ib. 
a.) Write a linear system to model this situation.

b.) How many boxes of each fruit were there? Graph, indicate your solution clearly and give the windows on your calculator. 
Mathematics
1 answer:
hammer [34]3 years ago
4 0
1) write a linear system - let a = boxes of apples and b = boxes of bananas
a + b = 86
32a + 16b = 1968

2) solve - use substitution
a = 86 - b
32(86 - b) + 16b = 1968
2752 - 32b + 16b = 1968
-16b = -784
16b = 784
b = 49
a + 49 = 86
a = 37

37 boxes of apples and 49 boxes of bananas
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krok68 [10]
For A+\frac{2}{a}-\frac{5}{a}+\frac{1}{a^2}-8a+15

Combine the fractions \frac{2}{a}  -  \frac{5}{a} \ \textgreater \  \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \  \frac{2-5}{a}


\mathrm{Subtract\:the\:numbers:}\:2-5=-3 \ \textgreater \  \frac{-3}{a}

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Therefore our final answer is A-\frac{3}{a}+\frac{1}{a^2}-8a+15

Hope this helps!
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sukhopar [10]

Answer: A. \left[\begin{array}{ccc}29&13\\13&10\\\end{array}\right]

Step-by-step explanation:

The question is asking us to find the product of the matrices. The key difference is the second A has a little <em>T</em> in the exponent. This <em>T</em> means transpose. You multiply A by the transpose of A. To find the transpose, you turn the rows into columns.

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Now that we have our transpose, we can multiply the matrices.

\left[\begin{array}{ccc}5&2\\3&-1\\\end{array}\right] \left[\begin{array}{ccc}5&3\\2&-1\\\end{array}\right] =\left[\begin{array}{ccc}5*5+2*2&5*3+2(-1)\\3*5+2(-1)&3*3+(-1)(-1)\\\end{array}\right] =\left[\begin{array}{ccc}29&13\\13&10\\\end{array}\right]

4 0
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