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1 year ago

1. What type of waves can only travel through a medium?

Physics

1 answer:

Sonbull [250]1 year ago

3 0

Answer:

A mechanical wave can only travel through a medium.

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If you apply an unbalanced force to this object it will ______. Mention all that will apply: change velocity, accelerate, change

Papessa [141]

Answer:

All of them: change velocity, accelerate, change position

Explanation:

We can answer this question by using Newton's second law:

F = ma

where

F is the net force on the object

m is the mass of the object

a is the acceleration

We notice that when there is an unbalanced force on the object, $F\neq 0$ , and therefore

$a\neq 0$

whcih means that the object will accelerate.

But acceleration is the rate of change of velocity, v:

$a=\frac{\Delta v}{\Delta t}$

And so,

$\Delta v \neq 0$

which means that the object will change velocity.

If the object is changing velocity, this means that it is also moving: therefore, the position of the object must be changing, so also the option "change position" is correct.

6 0

3 years ago

150 ml of water is heated with a burning marshmallow From 20 c to 93.5 C

kap26 [50]

93.5 if it’s wrong sorry sis I need my homework done too

7 0

3 years ago

A sheet of paper can be withdrawn from under a container of milk without toppling it if the paper is pulled A. gravity pulls ver

g100num [7]

C the milk carton has inertia
Inertia is an object not wanting to start moving when it's staying still, so the milk carton won't want to move and won't topple over

7 0

3 years ago

A rugby player sits on a scrum machine that weighs 200 Newtons. Given that the coefficient of static friction is 0.67, the coeff

Trava [24]

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

4 0

2 years ago

The far point of an eye is 180 cm. A corrective lens is to be used to allow this eye to focus clearly on objects a great distanc

sveticcg [70]

Answer:

The focal length of this lens is f = 0.55 D

Explanation:

Given that the far point of an eye ( d )= 180 cm = 1.8 m

We know that focal length of lens is given by

$f = \frac{1}{d}$

Put the value of d in above equation we get

$f = \frac{1}{1.8} \ m^{-1}$

f = 0.55 D

Therefore the focal length of this lens is f = 0.55 D

5 0

3 years ago