A sample of an ideal gas is heated, and its kelvin temperature doubles. The average speed of the molecules in the sample will increases by a factor of 
The root-mean square (RMS) velocity is the value of the square root of the sum of the squares of the stacking velocity values divided by the number of values. The RMS velocity is that of a wave through sub-surface layers of different interval velocities along a specific ray path.
Root mean square speed is a statistical measurement of speed.
The root mean square speed can be calculated as : V1 : 
if temperature becomes double
let T1 is initial temperature
So , T2 = 2 * T1
now ,
Root mean square speed will be (V2) = 
= *
= V1
Thus when temperature becomes double, the root mean square speed increases by a factor of
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Answer:
v = 4.4 m / s
Explanation:
Unfortunately, the exercise scheme does not appear. Let's analyze the problem the marble leaves point A with an initial velocity, goes down and then rises to a given height where its velocity is zero, in the whole trajectory they tell us that the resistance is zero, so we can use the conservation relations of the enegy.
Starting point. Point A
Em₀ = K + U = ½ m v2 + mg y_a
point B.
Em_f = U = m g y
the energy is conserved
Em₀ = Em_f
½ m v² + mg y_a = m g y
½ m v² = m g (y -y_a)
v = 
In the exercise the diagram is not seen, but the height of point A must be known, suppose that y_a = 4 m
v = 
v = 4.4 m / s
Answer:
The distance away the center of the earthquake is 1083.24 km.
Explanation:
Given that,
Speed of transverse wave = 9.1\ km/s
Speed of longitudinal wave = 5.7 km/s
Time = 71 sec
We need to calculate the distance of transverse wave
Using formula of distance
....(I)
The distance of longitudinal wave
....(II)
From the first equation
Put the value of t in equation (II)
Hence, The distance away the center of the earthquake is 1083.24 km.
