The pressure exerted by 0.57 moles of CO2 at a temperature of 25°C and a volume of 500 ml is 28 atm.
<u>Explanation:</u>
According to ideal gas law,
PV = nRT
where P represents the pressure of a gas,
V represents the volume of a gas,
n represents the number of moles,
R represents the gas constant = 0.0821 L atm / mol K.
T represents the temperature of a gas.
Given V = 500 ml = 0.5 l, T = 25°C = 298 K, n = 0.57 mol
PV = nRT
P = nRT / V
= (0.57 
0.0821 298) / 0.5
P = 28 atm.
The pressure of a gas is 28 atm.
The atom that is made up of two protons is He. The number of neutrons is also two. The number of electrons matters in the charge. So to make 10 electrons, we add 8 more. hence, 4/2 He 8-.
Answer: The pH of solution is 10.
The pOH of the solution is 4.
Explanation:
pH is the negative logarithm of concentration of hydrogen ion.
As given concentration of acidic solution is 
. Therefore, pH of the solution is calculated as follows.
![pH = -log [H^{+}]\\= -log (1.00 \times 10^{-10})\\= 10](https://tex.z-dn.net/?f=pH%20%3D%20-log%20%5BH%5E%7B%2B%7D%5D%5C%5C%3D%20-log%20%281.00%20%5Ctimes%2010%5E%7B-10%7D%29%5C%5C%3D%2010)
The relation between pH and pOH is as follows.
pH + pOH = 14
pOH = 14 - pH
= 14 - 10
= 4
Thus, we an conclude that pH of solution is 10 and pOH of the solution is 4.
The final gas pressure : 175.53 atm
<h3>Further explanation</h3>
Maybe the complete question is like this :
A ridged steel tank filled with 62.7 l of nitrogen gas at 85.0 atm and 19 °C is heated to 330 °C while the volume remains constant. what is the final gas pressure?
The volume remains constant⇒Gay Lussac's Law
<em>When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature </em>
P₁=85 atm
T₁=19+273=292 K
T₂=330+273=603 K
Glucose and Oxygen
Hope this helped you out
