Answer:
<u> </u><u>85.952 ml</u> 
needed to titrate the excess complexing reagent .
Explanation:
Lets calculate
After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml
As the number of moles of 
=
=
=0.01172
Molarity = 
=
=0.000586 moles
Excess of EDTA = concentration of EDTA - concentration of CoSO4
= 0.009005 - 0.000586
= 0.008419 M
As M1V1 ( Excess of EDTA ) = M2V2 
V2 =85.952 ml
Therefore , <u>85.952 ml </u> needed to titrate the excess complexing reagent .
Answer:
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Explanation:
Another name for them are called groups or families.
As i am reading the problem, i notice they give two concentrations (M), a volume and asking for the other volume; this should be a hint that we need to use the dilution formula---> M1V1 = M2V2
M1= 2.55 M
V1= ?
M2= 0.75 M
V2= 125 mL
now, we plug in the values into the formula
(2.55 x V1) = (0.75 x 125)
V1= 36.8 mL
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