Answer:
1) Activation energy ( A )
2) Molar concentration of XZ(g) ( C )
Explanation:
XZ(g) ⇄ 2XZ
1) <em>Activation energy </em><em>I</em>s decreased by the addition of a catalyst
while Equilibrium constant will Increase and other options will still remain unaffected
2)<em>Molar concentration of X</em><em>Z</em><em>(g) </em>Is deceased when the volume of the reaction vessel is increased and equilibrium is reestablished at 298 K
while Number of molecules present will Increase
I think it’s going to be 8, which is my best guess. Good luck
The equilibrium concentration of N₂ : 1.992
<h3>Further explanation</h3>
Given
Kc = 6.0 x 10⁻² at 500°C
0.253 M H₂ and 0.044 M NH₃
Reaction
3H₂(g) + N₂(g) = 2NH₃(g)
Required
The equilibrium concentration of N₂
Solution
Kc for the reaction :
Heat required = M * C * (delta T)
= (Mass)*(Specific heat)*(temperature change)
= 250 * 4.18* 52 = 54340Joules.
I solve when unit of specific heat is (J/gC) if have another unit please tell me