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kenny6666 [7]
3 years ago
8

How long does it take two skydivers to fall 150 m with acceleration of 9.80 m/s before they open their

Physics
1 answer:
sergejj [24]3 years ago
7 0
S = 1/2 g t^2
So t^2 = 2 S / g
So time = square root ( 300 / 9.80 )
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You are in a spacecraft moving at a constant velocity. The front thruster rocket fires incorrectly, causing the craft to slow do
Alchen [17]

Answer:

It continue to move forward at a constant velocity which will be slower than before the front thruster was fired.

Explanation:

Before the front thruster was fired, the spacecraft was already moving at a particular velocity.

After the malfunction, the front thruster is fired and then the force exerted by that front thruster slows the spacecraft down, as we are told.

By using the rear thruster to exert a force equal to that from the front thrusters, a force equal in magnitude to that of the front thrusters is added, cancelling out the effect of the front thrusters. Because the spacecraft is already moving at a slower speed at this point compared to the beginning, it continues to move at that speed.

8 0
4 years ago
1. How many paths through which charge can flow would be shown in a diagram of a series
Elanso [62]
1. One
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3 years ago
What exactly is Density? Please answer​
solmaris [256]

Answer:

density is the quantity per a unit volume, unit area or unit length.

Explanation:

7 0
3 years ago
A carnot heat engine receives 600 kj of heat from a source of unknown temperature and rejects 175 kj of it to a sink at 20°c. de
oee [108]

(b) 71%

The thermal efficiency of a Carnot heat engine is given by:

\eta = \frac{W}{Q_{in}}

where

W is the useful work done by the engine

Q_{in} is the heat in input to the machine

In this problem, we have:

Q_{in}=600 kJ is the heat absorbed

W=600 kJ-175 kJ=425 kJ is the work done (175 kJ is the heat released to the sink, therefore the work done is equal to the difference between the heat in input and the heat released)

So, the efficiency is

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(a) 737^{\circ}C

The efficiency of an engine can also be rewritten as

\eta = 1-\frac{T_C}{T_H}

where

T_C is the absolute temperature of the cold sink

T_H is the temperature of the source

In this problem, the temperature of the sink is

T_C = 20^{\circ}C + 273=293 K

So we can re-arrange the equation to find the temperature of the source:

T_H = \frac{T_C}{1-\eta}=\frac{293 K}{1-0.71}=1010 K\\T_H = 1010 K - 273=737^{\circ}C

7 0
3 years ago
Name two processes that release nuclear energy?
Kaylis [27]

Answer:  Nuclear energy is released from an atom through one of two processes: nuclear fusion or nuclear fission. In nuclear fusion, energy is released when the nuclei of atoms are combined or fused together. This is how the sun produces energy. In nuclear fission, energy is released when the nuclei of atoms are split apart.

Let me know if it helps!

7 0
3 years ago
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