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3 years ago

What are the components of the vector with a magnitude of 65.0 and a direction of 101.7°

Physics

2 answers:

artcher [175]3 years ago

8 0

<span>The correct answer is (63.6, -13.2)

</span>

soldier1979 [14.2K]3 years ago

3 0

Answer:

The components of the vector = (-13.18i, 63.65j)

Explanation:

Given;

magnitude of magnetic field strength, B = 65.0

direction of the magnetic field strength, θ = 101.7°

The vector has both y-component and x-component

The y-component of the vector is given as, Bsinθ,

The x-component of the vector is given as, Bcosθ,

The components of the vector = (x, y) = ( Bcosθ, Bsinθ)

The components of the vector = ( 65cos101.7°, 65sin101.7°)

The components of the vector = (-13.18i, 63.65j)

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Answer:

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Explanation:

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The electric field can be gotten by making E subject of formula:

E = K/(qr)

The electeic field needed to stop the electrons must be equal in magnitude to the electric field carried by these electrons:

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3 years ago

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Delvig [45]

Answer:

the length of stretched spring in cm is 22

Explanation:

given information:

spring length, x1 = 20 cm = 0.2 m

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the length of spring streches, x2 = 22 cm = 0.22 m

According to Hooke's law

F = - kΔx

k = F/*=(x2-x1)

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if the spring is now suspended from a hook and a 10.2-kg block is attached to the bottom end

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