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3 years ago

What are the components of the vector with a magnitude of 65.0 and a direction of 101.7°

Physics

2 answers:

artcher [175]3 years ago

8 0

<span>The correct answer is (63.6, -13.2)

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soldier1979 [14.2K]3 years ago

3 0

Answer:

The components of the vector = (-13.18i, 63.65j)

Explanation:

Given;

magnitude of magnetic field strength, B = 65.0

direction of the magnetic field strength, θ = 101.7°

The vector has both y-component and x-component

The y-component of the vector is given as, Bsinθ,

The x-component of the vector is given as, Bcosθ,

The components of the vector = (x, y) = ( Bcosθ, Bsinθ)

The components of the vector = ( 65cos101.7°, 65sin101.7°)

The components of the vector = (-13.18i, 63.65j)

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2 years ago

2 Points

goldfiish [28.3K]

Answer:

I believe it's called rolling friction

8 0

3 years ago

Read 2 more answers