That would be A.
2.5*2*10^(10-7)=5*10^3
Answer:
See explanation and image attached
Explanation:
The mechanism for both the hydroboration of 2-methyl-1-pentene and acid-catalyzed hydration are shown i the image attached to this answer.
The both processes involve addition reaction. Hydroboration is similar to hydration but the orientation of addition is anti - Markovnikov in nature.
The acid-catalyzed hydration of 2-methyl-1-pentene yields a minor product and a major product. The major product is an accordance with Markovnikov rule as shown by the reaction mechanism. The minor product is anti - Markovnikov.
Answer:
1.43 * 10^-2
Explanation:
Firstly, we need to get the ionization equation for lead I chloride. We can then get the Initial, change and equilibrium table of the lead and chloride ions that can help us calculate the molar solubility. This is shown as follows:
PbCl2(s) --> Pb2+(aq) + 2 Cl-(aq)
This shows that one mole of lead ii chloride will yield 1 mole of the lead ion and 2 moles of the chloride ion.
The ICE table is shown below:
Pb2+ 2Cl-
Initial 0.00 0.00
Change +s +2s
Equilibrium s 2s
Ksp = [Pb2+][Cl-]^2
Ksp = [s][2s]^2
Ksp = 4s^3
s^3 = Ksp/4
s = cube.root [Ksp/4]
s = cube.root[1.17 * 10^-5/4]
s = 1.43 * 10^-2
3Mg + N₂ → Mg₃N₂
n(Mg) = 12,2g÷24,4g/mol = 0,5mol - limiting reagente.
n(N₂) = 5,16g÷28g/mol = 0,18mol
n(Mg₃N₂):n(Mg) = 1:3, n(Mg₃N₂) = 0,166mol
m(Mg₃N₂) = 0,166mol·101,2g/mol = 16,8g.
%(N)= 2·Ar(N)÷Mr(Mg₃N₂) = 2·14÷101,2 = 27,66% = 0,2766
%(Mg) = 3·Ar(Mg)÷Mr(Mg₃N₂) = 3·24,4÷101,2 = 72,34%
or 100% - 27,66% = 72,34%.
