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Sauron [17]
3 years ago
15

BRAINLIESTTT ASAP!! PLEASE HELP ME :)

Chemistry
1 answer:
a_sh-v [17]3 years ago
3 0

Answer: true

Explanation:

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Igoryamba

Answer:

The arm that was not sprayed with anything

Explanation:

The control group would be <u>the arm that was not sprayed with anything</u>.

<em>The control group during an experiment is a group that forms the baseline for comparison in other to determine the effects of a treatment. The control group does not include the variable that is being tested and as such, it provides the benchmark to measure the effects of the tested variable on the other group - the experimental group. In this case, the experimental group would be the arm that was sprayed with the repellent.</em>

8 0
3 years ago
How many moles of bromine atoms are in 2.60×10^2 grams of bromine?
AlladinOne [14]
Your answer is 3.25 moles of Bromine

4 0
4 years ago
Which observation would best support that the bond present was a covalent bond?
DIA [1.3K]

Answer:

A covalent bond is present between two non-metals that share electrons in their molecular structure.

Explanation:

Examples of covalent bonds may be between carbon dioxide or water. And there may be three types of covalent bonds such as ionic, covalent and polar. In the first type, there is a transfer of an electron resulting in a gain for one of the atoms. In the second type, there is a sharing of electrons between the atoms. The third type is characterized by a difference in electronegativity between atoms.

4 0
3 years ago
If 3.0 atm of pure HN3(g) is decomposed initially, what is the final total pressure in the reaction container? What are the part
lawyer [7]

This is an incomplete question, here is a complete question.

Hydrogen azide, HN₃, decomposes on heating by thefollowing unbalanced reaction:

HN_3(g)\rightarrow N_2(g)+H_2(g)

If 3.0 atm of pure HN₃ (g) is decomposed initially,what is the final total pressure in the reaction container? Whatare the partial pressures of nitrogen and hydrogen gas? Assume thatthe volume and temperature of the reaction container are constant.

Answer : The partial pressure of N_2 and H_2 gases are, 4.5 atm and 1.5 atm respectively.

Explanation :

The given unbalanced chemical reaction is:

HN_3(g)\rightarrow N_2(g)+H_2(g)

This reaction is an unbalanced chemical reaction because in this reaction number of hydrogen and nitrogen atoms are not balanced on both side of the reaction.

In order to balance the chemical equation, the coefficient '2' put before the HN_3 and the coefficient '3' put before the N_2 then we get the balanced chemical equation.

The balanced chemical reaction will be,

2HN_3(g)\rightarrow 3N_2(g)+H_2(g)

As we are given:

The pressure of pure HN_3 = 3.0 atm

p_{Total}=2\times p_{HN_3}=2\times 3.0atm=6.0atm

From the reaction we conclude that:

Number of moles of N_2 = 3 mol

Number of moles of H_2 = 1 mol

Now we have to calculate the mole fraction of N_2 and H_2

\text{Mole fraction of }N_2=\frac{\text{Moles of }N_2}{\text{Moles of }N_2+\text{Moles of }H_2}=\frac{3}{3+1}=0.75

and,

\text{Mole fraction of }H_2=\frac{\text{Moles of }H_2}{\text{Moles of }N_2+\text{Moles of }H_2}=\frac{1}{3+1}=0.25

Now we have to calculate the partial pressure of N_2 and H_2

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 6.0 atm

X_i = mole fraction of gas

p_{N_2}=X_{N_2}\times p_T

p_{N_2}=0.75\times 6.0atm=4.5atm

and,

p_{H_2}=X_{H_2}\times p_T

p_{H_2}=0.25\times 6.0atm=1.5atm

Thus, the partial pressure of N_2 and H_2 gases are, 4.5 atm and 1.5 atm respectively.

8 0
3 years ago
Is it true that minerals come from orgainic
olga nikolaevna [1]
No but some minerals do
4 0
3 years ago
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