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Brrunno [24]
3 years ago
5

Ni (s) + O2 (g) → NiO (s)

Chemistry
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

Explanation:

2NiS + 3O2 = 2NiO + 2SO2

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A 2.00 liter evacuated container has a mass of 1050.0 g. When the container is filled with an unknown gas at 800. mm Hg pressure
Andrei [34K]

Answer:

(A) 28

Explanation:

To solve this problem we use the <em>PV=nRT equation</em>, where:

  • P = 800 mmHg ⇒ 800/760 = 1.05 atm
  • V = 2.00 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 25.0 °C ⇒ 25.0 + 273.16 = 298.16 K

We<u> input the data</u>:

  • 1.05 atm * 2.00 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

And <u>solve for n</u>:

  • n = 0.086 mol

Now we calculate the gas' mass:

  • Gas Mass = (Mass of Container w/ Gas) - (Mass of Empty Container)
  • Gas Mass = 1052.4 g - 1050.0 g = 2.4 g

Finally we <u>calculate the unknown gas' molar mas</u>s, using<em> its mass and its number of moles</em>:

  • Molar Mass = mass / moles
  • Molar Mass = 2.4 g / 0.086 mol = 27.9 g/mol

So the answer is option (A).

5 0
3 years ago
How does binomial nomenclature related to plants and animals?
goldenfox [79]

Answer:

Binomial Nomenclature is a two-term naming system that uses two different terms to name the species, plants, animals and living organisms. ... The two terms consist of a generic epithet which is genus (category) of that species, and specific epithet which indicates the species itself.

Explanation:

8 0
3 years ago
U ever get an answer
den301095 [7]
Yesn’t. they are either wrong or links
6 0
2 years ago
A 50.0 g sample of scandium, sc, is heated by exposure to 1.50 x 10 3 j. The temperature of the sc is raised by 61.1 o
statuscvo [17]

Given mass of Scandium = 50.0 g

Increase in temperature of the metal when heated = 61.1^{0}C

Heat absorbed by Scandium = 1.50*10^{3}J

The equation showing the relationship between heat, mass, specific heat and temperature change:

Q = m C (deltaT)

Where Q is heat = 1.50*10^{3}J

m is mass = 50.0 g

ΔT = 61.1^{0}C

On plugging in the values and solving for C(specific heat) we get,

1.50*10^{3}J=50.0g(C)(61.1^{0}C)

C = 0.491\frac{J}{g^{0}C }

Specific heat of the metal = 0.491\frac{J}{g^{0}C }

7 0
3 years ago
If I place a pot of water over a fire (heat source), what will happen to the water?
seropon [69]

Answer:

C. All of the water will get warm.

Explanation:

The water will get warm all together but slowly, eventually when it hits a certain high heated temperature it will start to boil.

6 0
3 years ago
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