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MissTica
3 years ago
5

Rank the following dienes in order of increasing stability:

Chemistry
1 answer:
gavmur [86]3 years ago
6 0

Answer:

1,2-pentadiene < 1,4-pentadiene < cis-1,3-pentadiene < trans-1,3-pentadiene

Explanation:

1,3-pentadiene have two double bonds which are in conjugation, due to which delocalization occur. Delocalization of electrons more provide stability to 1,3-pentadiene as compared to 1,4-pentadiene and 1,2-pentadiene.

Among cis form and trans form of 1,3-pentadiene, trans form is more stable beacuse of less steric hindrance.

1,2-pentadiene is an example of cumulated diene. 1,4-pentadiene is an isolated diene. Cumulated dienes are less stable as two double bonds are present on the same carbon which leads to high electron density.

So, 1,2-pentadiene will be the least stable.

Order of dienes from least stable to most stable is as follows:

1,2-pentadiene < 1,4-pentadiene < cis-1,3-pentadiene < trans-1,3-pentadiene

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Some hydrocarbons are regarded as unsaturated because they contain double or triple bonds between adjacent carbon atoms.

<h3>What are hydrocarbons?</h3>

Hydrocarbons are any organic compounds that contain hydrogen and carbon in its structure.

Hydrocarbons can be grouped into the following based on whether they contain single or double bonds:

  1. Saturated hydrocarbons - contain only single bonds e.g. alkanes
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Therefore, it can be said that some hydrocarbons are regarded as unsaturated because they contain double or triple bonds between adjacent carbon atoms.

Learn more about hydrocarbons at: brainly.com/question/17578846

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2 years ago
Rosa drew a flow chart of the carbon cycle.
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The correct Answer is A.

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3. Consumers eat producers (a primary level of consumer like a rabbit eats the producers or plants).

4. Decomposers return Carbon to the soil and release waste.

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7 0
3 years ago
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Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)
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Answer:

m_{CaCO_3}=0.179gCaCO_3

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3

Regards.

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3 years ago
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