Question

Find the area of a square with a side of length 2 Square root of 3+6 square root of 7 inches

Answer 1

Answer:

(264+24√21) in²

Step-by-step explanation:

Area of a square = Length * Length

A = L²

Given the length of a square as $2\sqrt{3}+6\sqrt{7}$ inches' The area of the square will be calculated as shown;

$A = (2\sqrt{3}+6\sqrt{7})^2\\\\A = (2\sqrt{3}+6\sqrt{7})(2\sqrt{3}+6\sqrt{7})\\\\A =(2\sqrt{3})(2\sqrt{3})+(2\sqrt{3})(6\sqrt{7})+(6\sqrt{7})(2\sqrt{3})+(6\sqrt{7})(6\sqrt{7})\\\\A = 4\sqrt{9}+12\sqrt{21}+12\sqrt{21}+36\sqrt{49}\\\\A = 4(3)+24\sqrt{21}+36(7)\\ \\A = 12+24\sqrt{21}+252\\\\A = 264+24\sqrt{21}$

Hence the area of the square is (264+24√21) in²