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galben [10]
3 years ago
7

Plz help me really need it 20 point plz plz thank you plz help me

Mathematics
1 answer:
Mama L [17]3 years ago
8 0

1. n=0

2. 1/3 0r .333333(to solve find the common denomenator then simplify after multiplying)

3. 294 ft.^3 (28*21*.5, you put .5 because 6in. is half a foot)

4. 37,410



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PLS HELP. here's ss in case anyone got confused last time lol
Varvara68 [4.7K]
Heyyy....I’m still confused. Nah jk but thx for the points lol
4 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
The equation x2 - 3x = 22
gizmo_the_mogwai [7]

Answer:

x = - 3.42443 or 6.42443

Step-by-step explanation:

5 0
3 years ago
8(2x – 14) + 13 = 4x – 27
Juliette [100K]
8 (2x - 14) + 13 = 4x -27

distribute 8 through the parentheses

16x - 112 + 13 = 4x - 27

combine like terms

16x - 99 = 4x -27

subtract 4x from each side

12x - 99 = -27

add 99 to each side

12x = 72

divide each side by 12

x = 6
3 0
3 years ago
Which point on the graph shows the amount of water in the bucket after 1 second? Hint: Type your answer in the form (x coordinat
Taya2010 [7]

Answer:

\displaystyle \left(1,\frac{5}{12}\right)

Step-by-step explanation:

<u>Graphs</u>

The graph shows the amount of water in gallons as a function of time in seconds.

We are required to find the amount of water in the bucked after 1 second. Since the graph does not show an exact location for t=1, we must find the equation of the line.

Two points are clear on the graph: (0,0) (12,5). This gives us the necessary information to find the equation of the line, which has the form:

w=mt+b

Where w is the amount of water in the bucket, t is the time, and m and b are two constants to be determined.

Using the point (0,0):

0=m(0)+b

It follows that b=0

The equation now takes the form:

w=mt

Using the point (12,5):

5=m(12)

We find m:

\displaystyle m=\frac{5}{12}

The final equation is:

\displaystyle w=\frac{5}{12}\cdot t

Substituting t=1:

\displaystyle w(1)=\frac{5}{12}\cdot (1)=\frac{5}{12}

The bucket has 5/12 gallons of water at t=1 second. Expressing the answer as an ordered pair:

\boxed{\displaystyle \left(1,\frac{5}{12}\right)}

6 0
3 years ago
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