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IRISSAK [1]
3 years ago
10

‼️need help please..

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0
If B is the center of that circle, then that statement is definitely false.  A central angle's degree measure is equal to the measure of the arc which it intercepts.  Keep in mind that arcs can be measured according to their LENGTH or to their DEGREE, and they are both very different from one another.  If arc AC is 65°, then the measure of angle ABC is also 65°
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What is the solution to this system
KonstantinChe [14]

Answer:

The answer is (2,3)

Step-by-step explanation:

5 0
3 years ago
How do u make 3/4 in a mix number as a whole number or decimal?
KengaRu [80]
In decimal form it's .75 and that's all you can make it
7 0
2 years ago
What is the first step in solving the equation
Varvara68 [4.7K]

Answer:

First Step: separate x^2 from -16

Second Step: add -16/25 to the other side.

Step-by-step explanation:

x^2 - 16/25 = 0

^^ this might be easier if you separate x^2 and -16

<em>First Step-</em>

so rewrite the problem as x^2/25  -16/25 = 0

then...

<em>Second Step-</em>

add -16/25 to the other side. This makes it: x^2/25 = 16/25

<em>Continuation-</em>

Now, you can multiply 25 on both sides to cancel it out.

so you have x^2 = -16

Message me if you want to solve for x.

4 0
3 years ago
Read 2 more answers
Two boxes are shaped as right rectangular prisms. The larger box is has a length of 24 cm, a width of 10 cm, and a height of 30
Vilka [71]
The dimensions of the smaller box are half those of the larger box. This means that:
*Length of smaller box= length of larger box/2= 24/2= 12cm.
*height of smaller box= height of larger box/2= 30/2= 15cm.
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4 0
2 years ago
Simplify the problem: Sin theta Sec Theta
kherson [118]

Answer:

\tan \theta

Step-by-step explanation:

We have to simplify the following expression as given by

\sin \theta \times \sec \theta

= \frac{\sin \theta}{\cos \theta}

= \tan \theta ( Answer )

Because, we know that \sec \theta =\frac{1}{\cos \theta} and \tan \theta = \frac{\sin \theta}{\cos \theta}

If we consider \sin \theta = \frac{Perpendicular}{Hypotenuse} and \sec \theta = \frac{Hypotenuse}{Base},

then \sin \theta \times \sec \theta = \frac{Perpendicular}{Hypotenuse}\times \frac{Hypotenuse}{Base} = \frac{Perpendicular}{Base}= \tan \theta

3 0
3 years ago
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