A driver slammed on her brakes and came to a stop with constant acceleration. Measurements on her tires and skid marks on the pa
1 answer:
Answer:
u = 29.22 m/s
Explanation:
distance (s) = 58.52 m
coefficient of kinetic friction (k) = 0.75
final velocity (v) = 0 m/s
acceleration due to gravity (g) = 9.8 m/s^{2}
How fast was she driving (u)
we can get how fast she was driving by using the formula below
s = ut - ...equation 1
where
- s = distance
- u = her initial velocity
- a = acceleration =
- k = coefficient of kinetic friction
- g = acceleration due to gravity
- t = time
from v = u - at (recall that v = 0)
0 = u - at, therefore t = u/a = u/kg
now substituting the required values above into equation 1 we have
s =
s =
u =
u =
u = 29.22 m/s
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Answer:
a) v = 16.57 m / s, b) a = 19.6 m / s², d) N = 1.76 10³ N, N / W = 3
Explanation:
This exercise looks interesting, but I think you have some problem with the writing, the questions seem a bit disconnected from the initial text.
Let's answer the questions.
a) For this part we can use energy considerations.
Starting point. The upper part of the trajectory indicates that the arm is horizontally
Em₀ = U = m g h
in this case h = r
Final point. For lower of the trajectory
Em_f = K = ½ m v²
as they indicate that there is no friction
Em₀ = em_f
mgh = ½ m v²
v =
let's calculate
v =
v = 16.57 m / s
b) the centripetal acceleration has the formula
a = v² / r
a = 16.57² / 14.0
a = 19.6 m / s²
c) see attached where the diagram is
where N is the normal and w the weight
d) let's use Newton's second law
N-W = m a
N - mg = m ar
N = m (g + a)
let's calculate
N = 60.0 (9.8 + 19.6)
N = 1.76 10³ N
the relationship with weight is
N / W = 1.76 10³/( 60 9.8)
N / W = 3
normal is three times greater than body weight
e) the answer is reasonable since by Newton's first law the body must continue in a straight line, therefore to change its trajectory a force must be applied to deflect it
Part 1) Which metal will cool the fastest?
To answer this question, we should have a look at the formula of the heat flow rate, which says "how fast" a material is able to heat/cool:
where:
is the heat exchanged
is the time interval
k is thermal conductivity of the material
A the surface where the exchange of heat occurs
the variation of temperature
x is the thickness of the material
We see that the heat flow rate
is linearly proportional to k, the thermal conductivity of the material. So, the larger k, the fastest the metal will cool.
If we have a look at the thermal conductivity of each metal, we find:
- Aluminium: 237 W/(mK)
- Copper: 401 W/(mK)
- Gold: 314 W/(mK)
- Platinum: 69 W/(mK)
Therefore, copper is the material with highest heat flow rate, so the metal which cools fastest.
Part 2) Which sample of copper demonstrates the greatest increase in temperature
To solve this part, we can have a look at how the amount of heat exchanged Q is related to the increase in temperature:
where m is the mass and Cs the specific heat of the material. Re-arranging the formula, we get
therefore, we see that the increase in temperature is inversely proportional to the mass m. This means that the block that will show the largest increase in temperature is the block with the smallest mass, so the correct answer is A) 0.5 kg.
To answer this question, we should have a look at the formula of the heat flow rate, which says "how fast" a material is able to heat/cool:
where:
k is thermal conductivity of the material
A the surface where the exchange of heat occurs
x is the thickness of the material
We see that the heat flow rate
If we have a look at the thermal conductivity of each metal, we find:
- Aluminium: 237 W/(mK)
- Copper: 401 W/(mK)
- Gold: 314 W/(mK)
- Platinum: 69 W/(mK)
Therefore, copper is the material with highest heat flow rate, so the metal which cools fastest.
Part 2) Which sample of copper demonstrates the greatest increase in temperature
To solve this part, we can have a look at how the amount of heat exchanged Q is related to the increase in temperature
where m is the mass and Cs the specific heat of the material. Re-arranging the formula, we get
therefore, we see that the increase in temperature is inversely proportional to the mass m. This means that the block that will show the largest increase in temperature is the block with the smallest mass, so the correct answer is A) 0.5 kg.