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2 years ago

X − 3y − 8z = −10 2x + 5y + 6z = 13 3x + 2y − 2z = 3

Engineering

1 answer:

nikitadnepr [17]2 years ago

7 0

Answer:

x - 3y - 8z = -10 2x + 5y + 6z = 13 3x + 2y - 2z = 3 => (-1+2z,2-2z,z)

Explanation:

x - 3y - 8z = -10 2x + 5y + 6z = 13 3x + 2y - 2z = 3

Solve using Gaussian Elimination

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Problem 1. A. Using singularity functions method, find out the equations for q, v, and M. B. Using appropriate boundary conditio

PIT_PIT [208]

Answer:

Hello the required diagram for the question is missing attached is the diagram AND A FREE BODY DIAGRAM

B)Rav = 3.375 KN Rbv = 4.625 KN

Explanation:

Attached is the detailed diagram of the bending moment diagrams and shear force

A) using singularity functions

y(x) = Displacement shape of Elastic curve

dy/dx = ∅ (x) ( slope )

d^2x/dy^2 = m(x) / E I ( moment function )

d^3x / dy^3 = I / EI V(x) ( shear function )

d^4x / dy^4 = I / EI q(x) ( loading function )

B) using the appropriate boundary conditions find out the constants

summation of F(x) = 0

Rah = 0

Rav - 8 + Rbv = 0

Rav + Rbv = 8 ----- equation 1

summation of M(a) = 0

= -8(4) + Rbv (8) - 5 = 0

therefore Rbv = 37 / 8 = 4.625 KN

insert the value of Rbv back into equation 1

Rav = 8 - 4.635 = 3.375 KN

C) ATTACHED ARE THE DIAGRAMS

7 0

3 years ago

A 60-kg person walks from the ground to the roof of a 74.8 m tall building. How much potential energy does she have at the top o

MArishka [77]

Answer:

44027.28 Joules

Explanation:

We know that Potential Energy of a body of mass 'm' is given by

$Potential Energy = m\times g\times h$

where

g= acceleration due to gravity with value = 9.81 $m/s^{2}$

h = height above the ground level

Applying given values in the formula we get

$Potential Energy = 60kg\times 9.81m/s^{2}\times74.8m$

Thus $Potential Energy= 44027.28Joules$

$Potential Energy= 44.027Kilo-joules$

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4 years ago

A 2 nominal schedule 40 PVC pipe is 75 ft long. It is to convey water. The available pump can provide a pressure drop of 1.84 ps

nexus9112 [7]

Answer:

10.22 m^3/s

Explanation:

To estimate the pressure drop in a pipe we use the Darcy-Weisbach equation

$\frac{(deltaP)}{L} =\alpha *(\frac{density}{2})*(\frac{v^{2}}{D})$ (equation 1)

With:

$\alpha$ = Darcy-Weisbach friction coefficient

L = length of duct or pipe

v = velocity of fluid

D= hydraulic diameter

Also flow rate is:

$Q=v*A$

Where v is:

$v=\frac{Q}{A}$

Area as a function of the diameter is:

$A=\pi *\frac{D^{2}}{4}$

$v=\frac{4*Q}{\pi*D^{2}}$ (equation 2)

For a laminar regime the the Darcy-Weisbach friction coefficient is function of the Reynolds number (Re) as:

$\alpha=\frac{64}{Re}$

$Re=\frac{density*v*D}{u}$

With: v =velocity, D= diameter if the pipe and u= viscosity.

With this information alpha would be:

$\alpha=\frac{64*u}{density*v*D}$ (equation 3)

Replacing equation 3 in equation 1 we have:

$\frac{(deltaP)}{L} =\frac{32*u*v}{D^{2}}$

And finally replacing the value for v in this equation we have:

$\frac{(deltaP)}{L} =\frac{128}{\pi}*\frac{u*Q}{D^{4}}$

Clearing for Q we get an expression to estimate the expected flow rate in the pipe.

$Q=\frac{deltaP}{L}*\frac{\pi}{128}*\frac{D^{4}}{u}$

We know

Delta P = 1.84 psi or $\frac{lb}{in^{2}}$

L= 75 ft or 900 in

D for a 2 nominal schedule 40 PVC is 2.047 in. In tables you find External diameter and internal diameter. For calculations you use internal diameter (ID)

U for water at 20°C is $2.034*10^{-5}\frac{lb*s}{ft^{2}}$ or $1.4113*10^{-7}\frac{lb*s}{in^{2}}$

$Q=\frac{1.84\frac{lb}{in^{2}}}{900in}*\frac{\pi}{128}*\frac{(2.047in)^{4}}{1.4113*10^{-7}\frac{lb*s}{in^{2}}} = 6.24*10^{3}\frac{in^{3}}{s}$

So the flow expected for this pipe is $6.24*10^{3}\frac{in^{3}}{s}$ or $10.22 \frac{m^{3}}{s}$

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What is Gentrification – The Role of Race, Land, and Property in Power – The Tradition of Anti-Capitalist Struggles – A Note on

vampirchik [111]

Answer:

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3 years ago

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Explain "unsupported assertions" and how these can land a particular side in trouble if they are made during a debate.

baherus [9]

The word "unsupported" implies that the argument being made lacks the necessary information to back it up. Therefore, "unsupported assertions" are claims that are made during a conversation or a debate, but which are made without enough evidence to back them up.

Making unsupported assertions during a debate can lead to trouble for the participants. When such a claim is made, it is stated as a fact. However, for the other team to accept it as such, it is necessary to show that there is enough evidence to support it. Being unable to provide this evidence not only renders the argument useless, but can damage the opinion that the audience has of the team that put forward the claim.

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3 years ago