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MAVERICK [17]
1 year ago
12

What is occurring in the image below?

Chemistry
1 answer:
DiKsa [7]1 year ago
3 0

The addictive quality is a reduction in vapour pressure.

The vapour pressure at a liquid's normal boiling point is the same as the ordinary atmospheric pressure, which is 1 atmosphere, 760 Torr, 101.325 kPa, or 14.69595 psi.

The pressure that results from liquids evaporating is known as vapour pressure. Surface area, intermolecular forces, and temperature are three often occurring variables that affect vapour press.

lower vapour pressure

raising the boiling point

Low-temperature depression

Osmotic force

They are all dependent on the solute; when you increase the solute, the colligative property and the ratio you added may change.

The Van't Hoff Factor is another option to examine (i). the number of dissolved ions. The colligative property will be further altered if the solute is ionic.

Learn more about Vapor pressure here brainly.com/question/14949391

SPJ1

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Hydrochloric acid reacts with calcium to form hydrogen and calcium chloride. If 100 grams of hydrochloric acid reacts with 100 g
LenaWriter [7]
Answer is hydrochloric acid

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5 0
3 years ago
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Given the following reaction: \ce{Cu + 2AgNO3 -> 2Ag + Cu(NO3)2}Cu+2AgNO3 ​ ​ 2Ag+Cu(NOX 3 ​ )X 2 ​ How many moles of \ce{Ag}
Alexandra [31]

Answer:

0.252 mol

Explanation:

<em>Given the following reaction: </em>

<em>Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂</em>

<em>How many moles of Ag will be produced from 16.0 g Cu, assuming AgNO3 ​ is available in excess.</em>

First, we write the balanced equation.

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂

We can establish the following relations.

  • The molar mass of Cu is 63.55 g/mol.
  • The molar ratio of Cu to Ag is 1:1.

The moles of Ag produced from 16.0 g of Cu are:

16.0gCu.\frac{1molCu}{63.55gCu} .\frac{1molAg}{1molCu} =0.252 molAg

6 0
3 years ago
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HELP! ASAP!
harina [27]

Given the model from the question,

  • The products are: N₂, H₂O and H₂
  • The reactants are: H₂ and NO
  • The limiting reactant is H₂
  • The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂

<h3>Balanced equation </h3>

From the model given, we obtained the ffolowing

  • Red => Oxygen
  • Blue => Nitrogen
  • White => Hydrogen

Thus, we can write the balanced equation as follow:

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

  • Reactants: H₂ and NO
  • Product: N₂, H₂O and H₂

<h3>How to determine the limiting reactant</h3>

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

3 moles of H₂ reacted with 2 moles of NO.

Therefore,

5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO

From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of H₂.

Thus, H₂ is the limiting reactant

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

8 0
2 years ago
70 points and will give brainliest
ikadub [295]

Answer:

74mL

Explanation:

Given parameters:

Molar mass of citric acid = 192g/mol

Molar mass of baking soda = 84g/mol

Concentration of citric acid  = 0.8M

Mass of baking powder = 15g

Unknown parameters:

Volume of citric acid = ?

Solution

       Equation of the reaction:

            C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Procedure:

  • We work from the known parameters to the unknown. From the statement of the problem, we can approach the solution from the parameters of the baking powder.
  • From the baking powder, we can establish a molar relationship between the two reactants. We employ the mole concept in this regard.
  • We find the number of moles of the baking powder that went into the reaction using the expression below:

                Number of moles = \frac{mass}{molar mass}

                Number of moles =  \frac{15}{84} = 0.179mole

  • From the equation of the reaction, we can find the number of moles of the citric acid:

             3 moles of baking powder reacted with 1 mole of citric acid

 0.179 moles of baking powder would react with \frac{0.179}{3}:

          This yields 0.059mole of citric acid

  • To find the volume of the citric acid, we use the mole expression below:

    Volume of citric acid = \frac{number of moles}{concentration}

Volume of citric acid = \frac{0.059}{0.8} = 0.074L

Expressing in mL gives 74mL

               

4 0
3 years ago
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I can’t see the picture for some reason but if I were to guess, I would say Pangea.
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