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1 year ago

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What is occurring in the image below?

1 answer:

DiKsa [7]1 year ago

3 0

The addictive quality is a reduction in vapour pressure.

The vapour pressure at a liquid's normal boiling point is the same as the ordinary atmospheric pressure, which is 1 atmosphere, 760 Torr, 101.325 kPa, or 14.69595 psi.

The pressure that results from liquids evaporating is known as vapour pressure. Surface area, intermolecular forces, and temperature are three often occurring variables that affect vapour press.

lower vapour pressure

raising the boiling point

Low-temperature depression

Osmotic force

They are all dependent on the solute; when you increase the solute, the colligative property and the ratio you added may change.

The Van't Hoff Factor is another option to examine (i). the number of dissolved ions. The colligative property will be further altered if the solute is ionic.

Learn more about Vapor pressure here brainly.com/question/14949391

SPJ1

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Which of the following statements are true of thermal energy and kinetic

Karolina [17]

Answer:

A. All the molecules or atoms in motion have kinetic energy.

B. All the molecules or atoms in motion have thermal energy.

C. Each molecule or atom in motion has thermal energy.

D. Each molecule or atom in motion has kinetic energy.

Explanation:

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2 years ago

Using the example in the above information determine the empirical formula of a compound if a sample contains 0.130 g of nitroge

olga2289 [7]

Answer: The empirical formula for the given compound is $NO_2$

Explanation : Given,

Mass of O = 0.370 g

Mass of N = 0.130 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.370g}{16g/mole}=0.0231moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{0.130g}{14g/mole}=0.00928moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00928 moles.

For Oxygen = $\frac{0.0231}{0.00928}=2.4\approx 2$

For Nitrogen = $\frac{0.00928}{0.00928}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of O : N = 2 : 1

Hence, the empirical formula for the given compound is $NO_2$

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3 years ago

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Murljashka [212]

Answer:

Heat is something you can't control

Explanation:

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2 years ago

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2 years ago

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strojnjashka [21]

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3 years ago

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