Question

if an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the lens what is the height of the image

Answer 1

To solve this problem we use an amplification formula for divergent lenses

$M = \frac{i}{o} = \frac{h'}{h}$

Where:

i: distance of the image to the lens

o: Distance from the object to the lens

h = height of the object

h '= height of the image

$M = \frac{4mm}{12mm} = \frac{h'}{18mm}$

$h'= 18mm\frac{4mm}{12mm}$

h '= 6 mm

The height is 6 mm