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Valentin [98]
3 years ago
13

if an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the lens what is the height

of the image
Physics
1 answer:
brilliants [131]3 years ago
5 0

To solve this problem we use an amplification formula for divergent lenses

M = \frac{i}{o} = \frac{h'}{h}

Where:

i: distance of the image to the lens

o: Distance from the object to the lens

h = height of the object

h '= height of the image

M = \frac{4mm}{12mm} = \frac{h'}{18mm}

h'= 18mm\frac{4mm}{12mm}

h '= 6 mm

The height is 6 mm

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the jet plane travels along the vertical parabolic path. when it is at point a it has speed of 200 m/s, which is increasing at t
givi [52]

Explanation:

Here is the complete question i guess. The jet plane travels along the vertical parabolic path defined by y = 0.4x². when it is at point A it has speed of 200 m/s, which is increasing at the rate .8 m/s^2. Determine the magnitude of acceleration of the plane when it is at point A.

→ The tangential component of acceleration is rate of increase in the speed of plane so,

a_{t} = v = 0.8 m/s^{2}

→ Now we have to find out the radius of curvature at point A which is 5 Km (from the figure).

dy/dx = d(0.4x²)/dx

         = 0.8x

Take the derivative again,

d²y/dx² = d(0.8x)/dx

          = 0.8

at x= 5 Km

dy/dx = 0.8(5)

         = 4

p = \frac{[1+ (\frac{dy}{dx})^{2}]^{\frac{3}{2} }   }{\frac{d^{2y} }{dx^{2} } }

now insert the values,

p = \frac{[1+(4)^{2}]^{\frac{3}{2} }  }{0.8}  = 87.62 km

→ Now the normal component of acceleration is given by

a_{n} = \frac{v^{2} }{p}

    = (200)²/(87.6×10³)

aₙ = 0.457 m/s²

→ Now the total acceleration is,

a = [(a_{t})^{2} +(a_{n} )^{2} ]^{0.5}

a = [(0.8)^{2} + (0.457)^{2}]^{0.5}

a = 0.921 m/s²

4 0
3 years ago
(help please no links )
trapecia [35]

Answer:

Hello, how's your day going?

if humanity came together and made a base on the moon, it would be revolutionary. The point of a base on the moon would have multiple purposes. for example, some think that the moon contains valuable metals such as iron and titanium. a base would serve as a place for workers harvesting metals to rest. Obviously or not most of the iron harvesting would be done automatically by robots and such.

If such a base were constructed on the moon, it would be the begining of people living on other worlds and would be a great start for a base on Mars.

Hope it helped

Spiky Bob

5 0
3 years ago
Two friends whisper at a volume of 20 decibels. Later, they converse at a volume of 40 decibels.
Yuki888 [10]
40 dB is 20 dB more power than 20 dB is. 20 dB more means 100 times as much.
4 0
3 years ago
Read 2 more answers
If the mass of the products measured 120 g, what would be the mass of the reactants? 30 g 60 g 120 g 240 g
Tanya [424]

Answer:

The correct answer option is C

Explanation:

In a balanced chemical reaction mass of the reactant are always equal to mass of the products. Also known as Law of Conservation of Mass  which states that " mass can nor be created nor be destroyed in a chemical reaction."

So, the mass of the reactant will be equal to the mass of products.That is 120 grams.

Hence, the correct answer option(C).

3 0
3 years ago
Read 2 more answers
A child is sitting on the seat of a swing with ropes 5 m long. Her father pulls the swing back until the ropes make a 30o angle
morpeh [17]

Answer:

v = 3.7 m/s

Explanation:

As the swing starts from rest, if we choose the lowest point of the trajectory to be the zero reference level for gravitational potential energy, and if we neglect air resistance, we can apply energy conservation as follows:

m. g. h = 1/2 m v²

The only unknown (let alone the speed) in the equation , is the height from which the swing is released.

At this point, the ropes make a 30⁰ angle with the vertical, so we can obtain the vertical length at this point as L cos 30⁰, appying simply cos definition.

As the height we are looking for is the difference respect from the vertical length L, we can simply write as follows:

h = L - Lcos 30⁰ = 5m -5m. 0.866 = 4.3 m

Replacing in the energy conservation equation, and solving for v, we get:

v = √2.g.(L-Lcos30⁰) = √2.9.8 m/s². 4.3 m =3.7 m/s

7 0
3 years ago
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