if an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the lens what is the height

Question

3 years ago

13

of the image

1 answer:

brilliants [131] · Answer 1 · 2022-08-25T21:10:37+03:00

5 0

To solve this problem we use an amplification formula for divergent lenses

$M = \frac{i}{o} = \frac{h'}{h}$

Where:

i: distance of the image to the lens

o: Distance from the object to the lens

h = height of the object

h '= height of the image

$M = \frac{4mm}{12mm} = \frac{h'}{18mm}$

$h'= 18mm\frac{4mm}{12mm}$

h '= 6 mm

The height is 6 mm