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Leviafan [203]
4 years ago
15

A capacitor stores 5.6 x 10-7 C of charge when connected to a 6.0-V battery. How much charge does the capacitor store when conne

cted to a 9.0-V battery? Number Units
Physics
1 answer:
Rina8888 [55]4 years ago
8 0

Answer:

nsnskdkxlxnckcvdodhxkccskzjxvxkxhLsbshsbHzv

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Which are uses of fiber optics? Check all that apply.
RideAnS [48]

Answer:

Transmission of telephone signals

Explanation:

Fiber optics are used for the transmission of telephone signals.

4 0
4 years ago
Read 2 more answers
A railroad car of 2000 kg coasting at 3.0 m/s overtakes and locks with an identical car coasting on the same track in the same d
serg [7]
The key is in "they lock together". This tells you this is a complete inelastic collision and therefore you can use the formula:
m1*v1+m2*v2=v(m1+m2)
Plug in numbers:
2000*3+2000*2=v(2000+2000)
so v=2 m/s, obviously in the same direction of motion in which they were both moving.
4 0
4 years ago
Milky Way Galaxy: Position of Solar System within this galaxy (where is earth)
ale4655 [162]
Do you mean what order the Earth is in? The planets in order from closest to farthest from the sun are: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune, and Pluto is technically just a dwarf planet but I'll include it anyways.
8 0
4 years ago
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At one instant of time a rocket is traveling in outer space at 2500m/s and is exhausting fuel at a rate of 100 kg/s. If the spee
lawyer [7]

Thrust is a reaction force described quantitatively by Newton's third law. When a system expels or accelerates mass in one direction, the accelerated mass will cause a force of equal magnitude but opposite direction on that system. Mathematically can be written as,

T = v\frac{dm}{dt}

Here,

v = speed of the exhaust gases measured relative to the rocket.

\frac{dm}{dt}= Rate of change of mass with respect to time

Our values are given as,

v = 1500m/s

\frac{dm}{dt} = 100kg/s

Replacing we have that

T = 1500*100

\therefore T = 1.5*10^5N

7 0
3 years ago
9. Una jeringa contiene cloro gaseoso, que ocupa un volumen de 95 mL a una presión de 0,96 atm. ¿Qué presión debemos ejercer en
masha68 [24]

Answer:

2.61 atm

Ley de Boyle

Explanation:

P_1 = Presión inicial = 0.96 atm

P_2 = Presión final

V_1 = Volumen inicial = 95 mL

V_2 = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=\dfrac{0.96\times 95}{35}\\\Rightarrow P_1=2.61\ \text{atm}

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.

4 0
3 years ago
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