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Bess [88]
3 years ago
13

When waves travel through water, why do the moving water particles continue to return to their starting position?

Physics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

Waves transfer energy, not matter

Explanation:

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The height of a cone is increasing at a rate of 10 cm/sec and its radius is decreasing so that its volume remains constant. How
ki77a [65]

Answer:

dr/dt = -2 cm/s.

Explanation:

The volume of a cone is given by:

V=\frac{1}{3} \pi r^{2}h (1)

  • r is the radius
  • h is the height

Let's take the derivative with respect to time in each side of (1).

\frac{dV}{dt}=\frac{1}{3} \pi \frac{d}{dt}(r^{2}h)=\frac{1}{3} \pi \left(2r\frac{dr}{dt}h+r^{2}\frac{dh}{dt} \right) (2)

We know that:

  • dh/dt = 10 cm / s (rate increasing of height)
  • dV/dt = 0 (constant volume means no variation with respect of time)
  • r = 4 cm
  • h = 10 cm

We can calculate how fast is the radius changing using the above information.

0=\frac{1}{3} \pi \left( 2\cdot 4\cdot \frac{dr}{dt} \cdot 10 + 4^{2}\cdot 10)\right  

Therefore dr/dt will be:

\frac{dr}{dt}=-\frac{160}{80}=-2 cm/s

The minus signs means that r is decreasing.

I hope it helps you!

6 0
3 years ago
Two forces have magnitudes in the ratio
rewona [7]

Answer:

F1=26N and F2=09N ..this is from the two simultaneously equations

8 0
3 years ago
An object that is 3 times higher than another object of the same mass will
uranmaximum [27]

Answer: I feel that 3 is the answer

Explanation: Let there be 2 objects, A and B

A is at height of 5m whereas B is at height of 15m

so over here let the gravitational potential energy of A be x

and since B is 3 times higher than A B=3x

Since, earth is considered to be the point where gravitational potenial is 0

So hence forth and object 3 times up will have 3 times the gravitational potential energy of A

3 0
3 years ago
How long will it take a ball to roll 10 meters along the floor at a speed of 0.5m/s
Julli [10]

Answer:

5s

Explanation:

because m/s=s/t so,

0.5m/s=10m/t

t=10m/0.5m/s

t=5sec

5 0
1 year ago
A baseball pitcher throws a ball horizontally at a speed of 34.0 m/s. A catcher is 18.6 m away from the pitcher. Find the magnit
Sidana [21]

To develop this problem, it is necessary to apply the concepts related to the description of the movement through the kinematic trajectory equations, which include displacement, velocity and acceleration.

The trajectory equation from the motion kinematic equations is given by

y = \frac{1}{2} at^2+v_0t+y_0

Where,

a = acceleration

t = time

v_0 = Initial velocity

y_0 = initial position

In addition to this we know that speed, speed is the change of position in relation to time. So

v = \frac{x}{t}

x = Displacement

t = time

With the data we have we can find the time as well

v = \frac{x}{t}

t = \frac{x}{v}

t = \frac{18.6}{34}

t = 0.547s

With the equation of motion and considering that we have no initial position, that the initial velocity is also zero then and that the acceleration is gravity,

y = \frac{1}{2} at^2+v_0t+y_0

y = \frac{1}{2} gt^2+0+0

y = \frac{1}{2} gt^2

y = \frac{1}{2} 9.8*0.547^2

y = 1.46m

Therefore the vertical distance that the ball drops as it moves from the pitcher to the catcher is 1.46m.

6 0
3 years ago
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