Answer:
θ = 33.54 rad
Explanation:
This is a circular motion exercise
θ= θ₀ + w₀ t + ½ α t²
suppose that for t = 0 the body is at its initial point θ₀ = 0 and from the graph we see that the initial angular velocity w₀ = -9.0 rad / s
we look for the angular acceleration,
α =
from the graph taken two points
α =
α = 3 rad / s²
we substitute in the first equation
θ = 0 -9 t + ½ 3 t²
the displacement is requested for t = 8.6 s
θ = = -9 8.6 + 3/2 8.6²
θ = 33.54 rad
Answer:
<em>vf=79.38 m/s</em>
<em>y= 321.5 m</em>
Explanation:
<u>Free Fall Motion</u>
A free-falling object falls under the exclusive influence of gravity. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is .
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:
1.
The penny will fall for t=8.1 s before hitting the ground, thus the height from which it was dropped is:
y= 321.5 m
2.
The final velocity is:
vf=79.38 m/s