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bogdanovich [222]
3 years ago
13

Một điện lượng 60mC dịch chuyển qua tiết diện thẳng của dây dẫn trong khoảng

Physics
1 answer:
lukranit [14]3 years ago
8 0

Answer:

3 (mA)

Explanation:

Cường độ dòng điện chạy qua dây dẫn này là:

I=△q△t=6,0.10−32=3.10−3 (A) = 3 (mA).\

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The diagram shows waves of sound travelling through the air. By which factor is the sound intensity decreased at 3 meters?
SIZIF [17.4K]
The diagram is missing; however, we know that the intensity of a sound wave is inversely proportional to the square of the distance from the source:
I(r)= \frac{1}{r^2}
where I is the intensity and r is the distance from the source.

We can assume for instance that the initial distance from the source is r=1 m, so that we put 
I= \frac{1}{r^2}= \frac{1}{(1)^2}=1
The intensity at r=3 m will be
I= \frac{1}{r^2}= \frac{1}{(3)^2}= \frac{1}{9}
Therefore, the sound intensity has decreased by a factor 1/9.
8 0
3 years ago
Read 2 more answers
Consider two straight wires lying on the x-axis, separated by a gap of 4 nm. The potential energy in the gap is about 3 eV highe
Tcecarenko [31]

Answer: 1.3 ×10^-31

Explanation:

the required probability is P = e^(-2αL)

Firstly, evaluate (-2αL)

α= 1/hc √2mc^2 (U - E)

h= modified planck's constant

where,

(-2αL)

= -(2L)/(h/2π ) ×√2mc^2 (U - E)

= -(2L) / (hc^2/π )×√2mc^2 (U - E)

(hc^2/2pi) = 197*eV.nm (standard constant)

2*L = 8 nm

mc^2 = 0.511×10^6 eV

Where m = mass electron

C= speed of light

(-2αL) = [-8nm/(197 eV.nm)] × (1.022× 10^6 eV*×3 eV)^0.5

(-2αL) = -71.1

Probability = e^(-2αL) = e^-71.1 = 1.3 ×10^-31

Therefore, the probability that a ondu tion ele tron in one wire arriving at the gap will pass through the gap into the other wire 1.3 ×10^-31.

3 0
3 years ago
A toy mouse has a mass of 4 kg and kinetic energy of 32 J. What is its speed? A. 6 m/s B. 3 m/s C. 5 m/s D. 4 m/s
Svetach [21]

32/4= 8

8/2=4

Answer : D. 4 m/s

7 0
3 years ago
Read 2 more answers
Which statements below are true?
Ilya [14]

The correct statements are that the speed decreases as the distance decreases and speed increases as the distance increases for the same time.

Answer:

Option A and Option B.

Explanation:

Speed is defined as the ratio of distance covered to the time taken to cover that distance. So Speed = Distance/Time. In other words, we can also state that speed is directly proportional to the distance for a constant time. Thus, the speed will be decreasing as there is decrease in distance for the same time. As well as there will be increase in speed as the distance increases for the same time. So option A and option B are the true options. So if there is decrease in the distance due to direct proportionality the speed will also be decreasing. Similarly, if the distance increases, the speed will also be increasing.

7 0
3 years ago
A flywheel flows from 250rpm to 150rpm in 4.2 seconds. How many revolutions occur during this time ​
Assoli18 [71]

Answer:

7revolutions

Explanation:

Given parameters:

Initial revolution  = 250rpm

Final revolution  = 150rpm

Time  = 4.2s

Unknown:

Number of revolutions that occur at this time = ?

Solution:

To solve this problem;

 let us find the change in revolution  = 250rpm - 150rpm  = 100rpm

Convert the time to seconds;

         60s makes 1 minute

        4.2s will make \frac{4.2}{60}   = 0.07min

So;

      The number of revolutions at this time  = 100rpm x 0.07min

         =   7revolutions

6 0
3 years ago
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