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Sav [38]
3 years ago
10

A packing crate is sitting at rest on an inclined loading ramp. How does the magnitude of the force of static friction compare t

o the other forces acting on the crate?
Physics
1 answer:
eduard3 years ago
8 0

As a crate is resting on the inclined surface of the ramp we have following forces on the crate

1. Weight of the crate vertically downwards

2. Normal force due to ramp perpendicular to the surface

3. static friction force along the ramp upwards

so here we know that crate is at rest

so we can say that

normal force is balanced by component of weight of crate

so we have

N = mg cos\theta

also we can say that friction force is balanced by another component of weight of the crate

F_f = mg sin\theta

so friction force is less than the weight of the crate and it will act opposite to it

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Soloha48 [4]

As the satellite panels extend, the angular velocity decreases due to drag force, and hence it will cause a decrease in the angular momentum of the satellite.

<h3>What is angular momentum?</h3>

Angular momentum is defined as the quantity of rotation of a body, which is the product of  mass, velocity and radius.

L = mvr

L = mωr²

where;

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As the satellite panels extend, the angular velocity decreases due to drag force, and hence it will cause a decrease in the angular momentum of the satellite.

Learn more about angular momentum here: brainly.com/question/4126751

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6 0
2 years ago
Gravity pulls downward on a rock with a force of 800 N. If you pull upward on the rock with a force of 400 N, what is the total
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The answer is
a. 400 N downward
3 0
3 years ago
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Series circuit when you had one bulb and battery voltage was at 9 volts, what was current into battery?
KengaRu [80]

Answer:

incomplete question, resistor must be there

Explanation:

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3 years ago
Which letter (A, B, or C) shows where you should apply the most effort to lift the stone?
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3 years ago
A 2100-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 5.00 m before coming into contact w
aliya0001 [1]

Answer:

   f = 878,080 N

Explanation:

mass of pile driver (m) = 2100 kg

distance of pile driver to steel beam (s) = 5 m

depth of steel driven (d) = 12 cm = 0.12 m

acceleration due to gravity (g0 = 9.8 m/s^{2}

calculate the average force exerted on the pile driver by the beam.

  • from work done = force x distance
  • work done = change in potential energy of the pile driver
  • equating the two equations above we have

               force x distance = m x g x (s - d)

              f x 0.12 = 2100 x 9.8 x (5- (-0.12))

              d = - 0.12 because the steel beam went down at we are taking its  

              initial position to be an origin point which is 0

              f = ( 2100 x 9.8 x (5- (-0.12)) ) ÷ 0.12

                   f = 878,080 N

4 0
3 years ago
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