Its called gauge pressure
The ratio would be 1:1 or in other terms the number of protons are equal to the number of neutrons and vice-versa.
Answer:
The rate of change of the distance is 14.89.
Explanation:
Given that,
Distance = 145 miles
Speed of car = 42 miles/hr
Distance covered by car = 55 miles
We need to calculate the the rate of change of the distance
According to figure,
Let OA is x, and AB is y.
Now, using Pythagorean theorem

On differentiating




Hence, The rate of change of the distance is 14.89.
Answer:
He is incorrect. Dissolving salt in water and evaporation of the water are both physical changes. The reappearance of salt is evidence that the change was reversible by a physical change, so it could not be a chemical change.
Answer:
The inventors claim is not real
a) No the the freezer cannot operate in such conditions
Explanation:
From the question we are told that
The power input is 
The rate of heat transfer 
The temperature of the freezer content is 
The ambient temperature is 
Generally the coefficient of performance of a refrigerator at idea conditions is mathematically represented as

substituting values


Generally the coefficient of performance of a refrigerator at real conditions is mathematically represented as

substituting values


Now given that the COP of an ideal refrigerator is less that that of a real refrigerator then the claims of the inventor is rejected
This is because the there are loss in the real refrigerator cycle that are suppose to reduce the COP compared to an ideal refrigerator cycle where there no loss that will reduce the COP