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nataly862011 [7]
3 years ago
13

1 What happens to the direction of the force on a current-carrying wire if the

Physics
1 answer:
sertanlavr [38]3 years ago
5 0

Answer:

<h2>If the forefinger points in the direction of the magnetic field and the middle finger in the direction of the current, then, the thumb points in the direction of the force exerted on the conductor.So, if the current is reversed in the conductor placed in a magnetic field the direction of force is also reversed..</h2>
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If the strings have the same thickness but different lengths, which of the following parameters, if any, willbe different in the
Vinil7 [7]

Answer:

If the strings have same thickness but different lengths then these parameters wave frequency, speed, wavelength will be different in the two strings. so the option d) None of the above is correct.

Explanation:

5 0
3 years ago
...............................................................
yuradex [85]

Answer:

true

Explanation:

when a ray of light travels from a less denser medium to a denser medium it tends to bend towards the normal.

5 0
2 years ago
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in a collusion, a 15 kg object moving with a velocity of 3 m/s transfers all of its momentum to a 5 kg object. what would be the
Hunter-Best [27]
According to momentum conservation
15*3 = 45kgm/s
and the velocity of 5 kg mass will be
45/5 = 9 m/s
7 0
3 years ago
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Why do animals that are least specialized have a better chance at survival?
Keith_Richards [23]
Animals that are the least specialized generally stand the best chance of survival when the environment suddenly and drastically changes because they're able to (Adapt to different conditions.)
4 0
3 years ago
A 75 kg bungee jumper leaps from a bridge. When he is 30 meters above the water, and moving at a speed of 20 m/s, the bungee cor
jasenka [17]

Answer:

k = 52.2 N / m

Explanation:

For this exercise we are going to use the conservation of mechanical energy.

Starting point. When it is 30 m high

        Em₀ = K + U = ½ m v² + m g h

Final point. Right when you hit the water

        Em_{f} = K_{e} = ½ k x²

in this case the distance the bungee is stretched is 30 m

        x = h

as they indicate that there are no losses, energy is conserved

        Em₀ = Em_{f}

       ½ m v² + m g h = ½ k h²

       k = \frac{m (v^{2} + 2 g h)}{h^{2} }

let's calculate

       k = \frac{75 \ ( 20^{2}  + 2 \ 9.8 \ 30)}{30^{2} }

       k = 52.2 N / m

3 0
2 years ago
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