The answer is that FRICTION PRODUCES HEAT.
Answer:

Explanation:
When the rock is immersed in unknown liquid the forces that act on it are shown as under
1) Tension T by the string
2) Weight W of the rock
3) Force of buoyancy due to displaced liquid B
For equilibrium we have 
=
When the rock is suspended in air for equilibrium we have

When the rock is suspended in water for equilibrium we have
+
=
Using the given values of tension and solving α,β,γ simultaneously for
we get

Solving for density of liquid we get


Answer:
m = 3.9 [m³]
Explanation:
We must remember that the density of the substance is defined as the relationship between mass over volume. That is expressed in the following equation:

where:
Ro = density = 1.3 [kg/m³]
m = mass [kg]
V = volume = 3 [m³]
Now replacing the values.
![m =Ro*V\\m = 1.3*3\\\\m=3.9[m^{3}]](https://tex.z-dn.net/?f=m%20%3DRo%2AV%5C%5Cm%20%3D%201.3%2A3%5C%5C%5C%5Cm%3D3.9%5Bm%5E%7B3%7D%5D)
Answer:
<h2>60 J</h2>
Explanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 3 × 10 × 2
We have the final answer as
<h3>60 J</h3>
Hope this helps you