<em>math</em><em>ematically</em><em>,</em>
<em></em>
<em>but</em><em> </em><em>weigh</em><em>t</em><em>=</em><em> </em><em>Force</em><em>.</em>
given pressure
18N/cm^2
and <em>Force</em> = 9000N
making <em>area</em> the subject in the relation above.
substitute their values into the equation
Answer:
a)V = 25.1 m/s
b)V = 4.226 m/s
Explanation:
Given that
x(t)=A t + B t²
A = -4.3 m/s
B = 4.9 m/s²
x(t)= - 4.3 t +4.9 t²
The velocity of the particle is given as
V=-4.3 + 4.9 x 2 t
V= - 4.3 + 9.8 t m/s
Velocity at point t= 3 s
V= - 4. 3 + 9.8 x 3 m/s
V= - 4.3 + 29 .4 m/s
V = 25.1 m/s
At origin :
x= 0 m
0 = - 4.3 t +4.9 t²
0 = - 4.3 + 4.9 t
t=0.87 s
The velocity at t= 0.87 s
V= - 4.3 + 9.8 t m/s
V= - 4. 3 + 9.8 x 0.87 m/s
V= - 4.3 + 8.526 m/s
V = 4.226 m/s
a)V = 25.1 m/s
b)V = 4.226 m/s
