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3 years ago

Electron dot structure for Acetophenone??

Chemistry

1 answer:

Natali [406]3 years ago

3 0

Search it on the internet it’s easier

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Substance A undergoes a first order reaction A  B with a half- life of 20 min at 25 °C. If the initial concentration of A ([A]◦

nydimaria [60]

The concentration of A will be 0.34 mol·L⁻¹ after 60 min.

In a first-order reaction, the formula for the amount remaining after n half-lives is

$\text{[A]} = \frac{\text{[A]}_{0}}{2^{n}}\\$

If $t_{\frac{1}{2}} = \text{20 min}\\$

$n = \frac{t}{t_{\frac{1}{2}}} = \frac{\text{60 min}}{\text{20 min}}= \text{3.0}$

∴ $\text{[A]} = \frac{\text{2.7 mol/L}}{2^{3.0}} = \frac{\text{2.7 mol/L}}{8.0} = \textbf{0.34 mol/L}$

6 0

3 years ago

Calculate the energy of a photon having a wavelength of 7.71 x 10^-5 m.

Bad White [126]

Answer:

Calculate the energy of a photon having a wavelength of 7.71 x 10^-5 m.

Explanation:

5 0

3 years ago

I need help with this pleae

pantera1 [17]

Depositional landforms are the visible evidence of processes that have deposited sediments or rocks after they were transported by flowing ice or water, wind or gravity. Examples include beaches, deltas, glacial moraines, sand dunes and salt domes

3 0

3 years ago

Which of the following has 20 neutrons? A. oxygen B. zirconium C. potassium D. neon

zavuch27 [327]

It think the answer is D

8 0

3 years ago

When rubidium ions are heated to a high temperature, two lines are observed in its line spectrum at wavelengths (a) 7.9 × 10−7 m

svetlana [45]

Answer:

The frequencies of the two lines are:

a) $3.79\times 10^{14} s^{-1}$

b) $7.14\times 10^{14} s^{-1}$

When we heat rubidium compound we will see red color.

Explanation:

$\nu=\frac{c}{\lambda }$

c = speed of light

$\lambda$ = wavelength of light

a) Frequency of the light when wavelength is equal to $7.9\times 10^{-7} m$

$\nu=\frac{c}{\lambda }$

$\nu=\frac{3\times 10^8m/s)}{7.9\times 10^{-7}}$

$\nu=3.79\times 10^{14} s^{-1}$

This frequency corresponds to red light

b) Frequency of the light when wavelength is equal to $4.2\times 10^{-7} m$

$\nu=\frac{c}{\lambda }$

$\nu=\frac{3\times 10^8m/s)}{4.2\times 10^{-7}}$

$\nu=7.14\times 10^{14} s^{-1}$

This frequency corresponds to violet light

When we heat rubidium compound we will see red color.

4 0

3 years ago